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How can you calculate weight of object in water if original weight of object displaced and amount of water is given?
Here's one way that would work: 1. Weigh a bowl of water. 2. Hold the object underwater with a piece of wire or straw and mark the higher water level with a grease marker. 3. Fill the bowl to the line with more water and weigh it again.
How is the buoyant force on a floating object related to weight of water it displaces?
if the water is heavier than the item inside it, then the water sinks to underneath the object. if the object is heavier then the object will sink under the water.
Calculate the water displace in water?
The water displacement in water can be calculated using Archimedes' principle. It states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. So, to calculate water displacement, you would need to determine the weight of the object and divide it by the density of water (which is approximately 1000 kg/m^3).
What makes an object seem to weight less when you hold it in a pool of water?
This phenomenon is called buoyancy and is caused by the object displacing water equal to its volume. If the weight of the object is less than the weight of this displaced water, then the object has positive buoyancy and will float. If the weight of the object is exactly equal to the weight of this displaced water, then the object has neutral buoyancy and thus be weightless. If the weight of the object is greater than the weight of this displaced water, then the object has negative buoyancy and will sink but it still weighs less than it did out of the water.Just remember buoyancy only affects the weight of the object, it has no effect on the mass of the object which remains constant in or out of water.
How much more does an object weigh after it has been submerged out of water?
Submerged "out-of-water". That is not possible. It is either submerged or it is out of water. Even when an object is submerger or partically submerged it will not weigh less. The physical characteristics (weight) of the object cannot be changed. The object, when placed in water will displace a certain amount of water and the object will float if the weight of the displaced water is more that the weight of the object. The object will then sink if it weighted more that the weight of the water it displaces. That said, the actual weight of the object doesnt change but if a scale were attached to it while hanging in air, it would read greater that when the object is floating or submerged in water.
How can you calculate weight of object in water if original weight of object displaced and amount of water is given?
Here's one way that would work: 1. Weigh a bowl of water. 2. Hold the object underwater with a piece of wire or straw and mark the higher water level with a grease marker. 3. Fill the bowl to the line with more water and weigh it again.
How much would someone weigh under water?
It depends on the density of the object that weighs one pound, and how much of it is under water. The object will weight 1lb - water density * object volume under water; If the object is on average is less dense the water (i.e. is buoyant), and is allowed to swim, its weight will be 0 because proportion of its volume under water will compensate gravity exactly.
How is the buoyant force on a floating object related to weight of water it displaces?
if the water is heavier than the item inside it, then the water sinks to underneath the object. if the object is heavier then the object will sink under the water.
This force acts upwards on objects suspended in water or air what is it?
It is called buoyant force. It is calculated by determining the volume of water displaced by the object, which is the volume of the object under water.The weight of this quantity of water is the buoyant force. It can also be calculated by knowing the depth of the object in the water, the pressure at that depth, and the area of the bottom of the object. Buoyant Force = Pressure * depth It can also be calculated by knowing the weight of the object. If an object is floating the water is supporting the object's weight. So the buoyant force = weight of object
Calculate the water displace in water?
The water displacement in water can be calculated using Archimedes' principle. It states that the buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. So, to calculate water displacement, you would need to determine the weight of the object and divide it by the density of water (which is approximately 1000 kg/m^3).
Does water affect the weight of an object the same thing as does submerging something in water affect the weight of an object?
Yes, when the object is submerged in water then water exerts opposite buoyonci force which decrease the weight of object.
What happens when the water around objects have a force greater than the object's weight?
The water around floating object's is a measure of that object's "Displacement". For the object to float the weight of displacement must equal the object's weight. If the water around an object is of a greater weight than an object's displacement, then the object will sink.
What is water buoyancY?
The difference between an object's weight, and the weight of water with the same volume as the object.
What is Archimedes princible?
Archimedes principle states that : The force of buoyancy is equal to the weight of the displaced water. If the weight of the water displaced is less than the weight of the object , the object will sink. Otherwise the object will float , with the weight of the water displace equal to the weight of the object.
What makes an object seem to weight less when you hold it in a pool of water?
This phenomenon is called buoyancy and is caused by the object displacing water equal to its volume. If the weight of the object is less than the weight of this displaced water, then the object has positive buoyancy and will float. If the weight of the object is exactly equal to the weight of this displaced water, then the object has neutral buoyancy and thus be weightless. If the weight of the object is greater than the weight of this displaced water, then the object has negative buoyancy and will sink but it still weighs less than it did out of the water.Just remember buoyancy only affects the weight of the object, it has no effect on the mass of the object which remains constant in or out of water.
What effect does buoyant force have on a submerged object?
The weight of the water displaced by the object is subtracted from the actual weight of the object (out of water), leaving the object with a net positive weight while submerged.
How do you calculate the density of an irregularly shaped object that floats in water?
If an object floats in water, we can immediately conclude that it is less dense than the water. So, we've already gained a bit of information. But can we learn more? Yes. We can further "ballpark" our estimate of the object's density through additional observation and deduction. About how much of the object is submerged? If, say, 75 percent of the object is under water, we can then say that its relative density -- that is, its specific gravity -- is about 0.75. In other words, it has a density of 0.75 grams per milliliter or, equivalently, 0.75 grams per cubic centimeter. (Note that the density of water is 1.00 gram per milliliter.) But can we do better? I think so. If we measure the volume of water displaced by the object when it is placed into the container of water, we can calculate the weight of the object, because its weight will be equal to the weight of the water it displaces. If the floating object displaces, say, 100 milliliters of water, then we know it weighs 100 grams, because, as noted above, the density of water is one gram per milliliter. But we're not done. To calculate an object's density, we must know its volume as well as its mass. From the measurement above, we know the object's weight , but we don't know its volume, mainly because of its irregular shape. But if we carefully push the object completely under water, it will displace an amount of water equal to its volume. Let's say that when we submerge the object fully, it displaces 130 milliliters of water. We therefore conclude that its volume is 130 milliliters, which is equal to 130 cubic centimeters. Since the object weighs 100 grams and has a volume of 130 cubic centimeters, its density is 100 grams/130 cubic centimeters = 0.769 g/cm3.
