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-- You say to yourself "Work is force times distance".

-- Then you ask "What's the force ?", you look at the question, and you say "47 N".

-- Then you ask "What's the distance ?", you look at the question, and you say "0.25 m".

-- Then you remember that "Work is force times distance", and you calculate (47 N) x (0.25 m) = 11.75 joules . -- As you hand in the test, you say to yourself "The mass of the pencil and

the resisting force of friction were only there to confuse me, but they failed."

--Then you smile :)

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Q: How do you calculate the work done by a 47N force pushing a .025k pencil .25m against a foce of 23N?
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