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Suppose (for simplicity) that n = 2k for some entire k. Let T(n) the time used to sort n elements. As we can perform separation and merging in linear time, it takes cn time to perform these two steps, for some constant c. So, T(n) = 2T(n/2) + cn.

In the same way:

T(n/2) = 2T(n/4) + cn/2, so

T(n) = 4T(n/4) + 2cn. Going in this way ... T(n) = 2mT(n/2m) + mcn, and

T(n) = 2kT(n/2k) + kcn = nT(1) + cnlog2n = O(n log n). Remember, as n=2k k = log2n! The general case requires a bit more work, but it takes O(n log n) time anyway.

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Q: How do you calculate time complexity for merge sort?

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The worst case for merge sort is O(n*log2n) The running time for merge sort is 2T(n/2)+O(n) I hope this will help... Jimmy Clinton Malusi (JKUAT-Main Campus)

Qucik sort or merge sort with time complexity O(n log n). In terms of both time and space Qucik sort is efficient.

MergeSort has the same time-complexity in all cases, O(n log n). In fact, it has exactly the same absolute time, no matter what the state of the array.

The time-complexity of merge sort is O(n log n). At each level of recursion, the merge process is performed on the entire array. (Deeper levels work on shorter segments of the array, but these are called more times.) So each level of recursion is O(n). There are O(log n) levels of recursion, since the array is approximately halved each time. The best-case time-complexity is also O(n log n), so mergesort takes just as long no matter what the existing state of the array.

The time complexity of an algorithm is the length of time to complete the algorithm given certain inputs. Usually, the algorithm with the best average time will be selected for a task, unless it can be proven that a certain class of conditions has to exist for an average time, in which case an algorithm that is faster in certain cases will be chosen based on that characteristic.For example, given the option of a merge sort or a bubble sort, a programmer might be tempted to say that the merge sort would be faster, on average, than a bubble sort. It so happens that they are correct; the merge sort is probably the better of the two options.However, if the data is usually "almost" sorted and rarely has out of place elements, then the bubble sort, despite being an inferior algorithm, would be faster than a merge sort for large data sets, which has a fixed time complexity that is better than bubble sort's average time complexity, but worse than bubble sort's best time complexity.Thus, an informed programmer would look at all the possible algorithms available to solve a task, and select the one that yields the best results for the majority of test cases. This is similar to how a business manager might compare the overall cost of acquisition with the cost of ownership over time to determine the best solution.

O(n2)

The worst case time-complexity for bubble sort algorithm is O(n*n).

The algorithm will have both a constant time complexity and a constant space complexity: O(1)

O(n^2)

n log n

O(n*n)

The time complexity of q-sort algorithm for all cases: average-O(n log(n)) worst- O(n2)

If the range of numbers is 1....n and the size of numbers is k(small no.) then the time complexity will be theta n log..

quadratic running time Θn^2

quick sort has a best case time complexity of O(nlogn) and worst case time complexity of 0(n^2). the best case occurs when the pivot element choosen as the center or close to the center element of the list.the time complexity can be derived for this case as: t(n)=2*t(n/2)+n. whereas the worst case time complexity for quick sort happens when the pivot element is towards the end of the list.the time complexity for this can be derived using the recurrence eqn: t(n)=t(n-1)+n

(n(n+1)) / 2

Merge sort (or mergesort) is an algorithm. Algorithms do not have running times since running times are determined by the algorithm's performance/complexity, the programming language used to implement the algorithm and the hardware the implementation is executed upon. When we speak of algorithm running times we are actually referring to the algorithm's performance/complexity, which is typically notated using Big O notation. Mergesort has a worst, best and average case performance of O(n log n). The natural variant which exploits already-sorted runs has a best case performance of O(n). The worst case space complexity is O(n) auxiliary.

Bubble sort has a time-complexity of O(nn) to sort n elements. Any sorting algorithm with a time-complexity of O(nn) is highly inefficient. The only thing in its favour is that it is stable (the input order of like elements is retained), but there are more efficient ways to perform a stable sort.

Bubble sort and insertion sort both have the same time complexity (and space complexity) in the best, worst, and average cases. However, these are purely theoretical comparisons. In practical real-world scenarios, insertion sort (or any other sort, for that matter) will almost always be the better choice over a bubble sort.

Merging two or more already sorted data-files.

what do you mean by time and space complexity and how to represent these complexity

time complexity is 2^57..and space complexity is 2^(n+1).

Selection sort has no end conditions built in, so it will always compare every element with every other element.This gives it a best-, worst-, and average-case complexity of O(n2).

you can find an example in this link ww.computing.dcu.ie/~away/CA313/space.pdfgood luck