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You can use Plank's relation to calculate the energy of the absorbed photon.

E = h.f = h.c/L

given

E = Energy of a photon in Joules

f = frequency of the photon in s-1

c = speed of light in m/s

L = wavelength of the photon in metre

h = Planck constant = 6.62606957×10−34 J.s

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11y ago
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14y ago

Solve

c = lambda*f

where lambda is wavelength, and f is frequency and c is the speed of light.

given two can find the third.

else, if energy is known

E = hf can E = hc / lambda can be applied to find frequency of lambda.

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15y ago

speed of light (C)= wavelength (?) x frequency (v) C is the constant in the equation which equals 3.00 x 108 The frequency would be given in the problem and from there you divide C/v

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12y ago

im not sure i need some one to answer it for me please

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12y ago

The wavelength is the ratio between the speed of light and the frequency.

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13y ago

Energy is related to wvelength by E = hc/wavelength = 2E-25/wavelengthm where h is Planck's Constant and c is the speed of light.

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11y ago

Wave length = (speed)/(frequency)

'Speed' of the photons is the 'speed of light'.

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15y ago

speed of light (C)= wavelength (λ) x frequency (v) C is the constant in the equation which equals 3.00 x 108 The frequency would be given in the problem and from there you divide C/v

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It tells you that the longer the wavelength the lower the energy. From the wavelength, one can also calculate the actual energy by using E = cxh/lambda where c is speed of light, h is Plank's constant and lambda is the wavelength.


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