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Given the point P = (a, b) and slope m, the point-slope equation is
(y - b) = m*(x - a)
y - b = mx - ma
y = mx - ma + b
which can be re-written as
y = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
Given the point P = (a, b) and slope m, the point-slope equation is
(y - b) = m*(x - a)
y - b = mx - ma
y = mx - ma + b
which can be re-written as
y = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
Given the point P = (a, b) and slope m, the point-slope equation is
(y - b) = m*(x - a)
y - b = mx - ma
y = mx - ma + b
which can be re-written as
y = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
Given the point P = (a, b) and slope m, the point-slope equation is
(y - b) = m*(x - a)
y - b = mx - ma
y = mx - ma + b
which can be re-written as
y = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
Wiki User
∙ 11y ago
Wiki User
∙ 11y agoGiven the point P = (a, b) and slope m, the point-slope equation is
(y - b) = m*(x - a)
y - b = mx - ma
y = mx - ma + b
which can be re-written as
y = mx + (b - ma) which is of the slope-intercept form y = mx + c in which c = b - ma.
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Write the equation in slopeintercept form of the line that has a slope of 2 and contains the point 3 7?
y = 2x + 1.
Write the equation in slopeintercept form of the line that has a slope of 3 and contains the point 2 5?
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The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
What are pointslope equations of the line going through -4 and -7 and 3 and 2?
Assuming the two points are (-4,-7) and (3,2) the equation for the slope would be (3-(-4))/(2-(-7)) which equals 7/9. If we use y=mx+b and the point (3,2) you get 2=(7/9)*3+b which simplifies to 2=2 1/3+b then by subtracting 2 1/3 from both sides you are left with b= -1/3. Thus the equation is y=7/9x-1/3.
How do you turn standard equations in slope intercept equations?
slopeintercept equations are used to find the slope and intercept (obviously lol) they are set up like this y=mx+b m is the slope and b is the y-intercept lets say you have an equation like... 2x + y = 5 (now minus 2x from both sides) 2x - 2x + y = 5 - 2x (simplify) y = 5 - 2x just use algebra to turn the standard form to slope intercept form
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