The value of 4.9 kW is equal to 4900 watts. Use the following equation to find the amperage for your question. I = W/E, Amps = Watts / Volts.
Either the supply or the multimeter is faulty.
The supply is probably 400 v three-phase with 230 v between each live and neutral. On this assumption the current is 49 amps and the copper cable size is 16 mm2 for a run of up to 30 metres.
You could run 30 low-energy lights, enough to light about three houses, or you could run about 10 laptop computers, or 2-3 tower-type computers. Also phone chargers, home audio and video recorders. Not high-power things like irons, convector heaters, kettles or cookers.
Very easy. There are 1,000 mL in one liter. So, simply multiply liters by 1,000 to get mL:49 L x 1,000 = 49,000 mL
No, 49 teaspoons are less than 49 pints.
Answer: 49 km = 30.4471 mi.
Answer: 49 ºF = 9.4 ºC
To convert 0.49 to percent multiply by 100: 0.49 × 100 = 49 %
49 inches
Divide by seven
Either the supply or the multimeter is faulty.
49ºF = 9.4ºC
49/50
- 94/5 + 915/16 + 94/15 = -49/5 + 159/16 + 139/15 = -2352/240 + 2385/240 + 2224/240 = 2257/240 = 997/240
1 meter is equal to 100 centimeters so 49 m = 4900 cm.
Without more information you cannot.
The supply is probably 400 v three-phase with 230 v between each live and neutral. On this assumption the current is 49 amps and the copper cable size is 16 mm2 for a run of up to 30 metres.