1 mEq=1 mmol/valence e.g.For sodium, 1 mEq=1mmol/1 (valence of sodium=1) means, 1 mmol sodium=1 mEq of sodium take for calcium,valence=2 1 1 mEq of calcium=1mmol/2=0.5 mmol of calcium
BaCl2 + Na2CO3 --> BaCO3 + 2NaCl Barium carbonate is the precipitate. 55ml x 0.1 M = 5.5 mmol Ba 40ml x 0.15 M = 6.0 mmol CO3 Thus limiting reagent is Ba. Molar mass barium carbonate = 137 + 12 + 3 x 16 = 197 g/mole = 197 mg/mmol 5.5 mmol x 197 mg/mmol = 1083.5 mg Round for sig figs .... 1080 mg barium carbonate
10 mM tartaric acid (sodium) buffer solution (pH=4.2) Tartaric acid (M.W.=150.09)..........................2.5 mmol (0.375 g) Sodium tart rate dihydrate (M.W.=230.08)........7.5 mmol (1.726 g) Add water to make up to 1 L. 10 mM tartaric acid (sodium) buffer solution (pH=2.9) Tartaric acid (M.W.=150.09)..........................7.5 mmol (1.13 g) Sodium tartrate dihydrate (M.W.=230.08)........2.5 mmol (0.58 g) Add water to make up to 1 L.
A mmol is a mmol but the amount of matter is different for each chemical.
0.035
1 mmol sodium = 23 mg sodium chloride 80 mmol sodium chloride = 80 x 23= 1840 mg sodium chloride
2300 mg ,2.3gm
136MG
500 mL * 100(mMol/mL) = 50 mMol NaHCO3 , hence50 mMol NaHCO3 = 50(mMol) * 84(mg/mMol) = 4200 mg = 4.2 g NaHCO3 in 500 mL
1 month to < 1 year < 3,8 mg/mmol 1 year to < 6 years < 3,3 mg/mmol 6 years to < 11 years < 2,7 mg/mmol 11 years to < 16 years < 2,1 mg/mmol ≥ 16year males < 2,5 mg/mmol, females < 3,5 mg/mmol
divide the mg of creatinine by 113 mg/mmol (molecular weight) of creatinine and the units will be in mmol
The answer is 0,02552 mmol.
4.12 mmol is 2.48112242e+24mg
1 mEq=1 mmol/valence e.g.For sodium, 1 mEq=1mmol/1 (valence of sodium=1) means, 1 mmol sodium=1 mEq of sodium take for calcium,valence=2 1 1 mEq of calcium=1mmol/2=0.5 mmol of calcium
4.98mmol
E.W= Molecular weight / # of ions = 100.09 (mg/mmol) /2 (meq/mmol) =50.043 mg/meq
what is the factor ( times ) to convert milligrams/DeciLitre to mmol/L