Want this question answered?
8
103
5
Count them: 643(10)=1010000011(2)
8 bits if unsigned, 9 bits if signed
23 can be represented in binary as 10111 and would therefore require 5 bits to represent.
16 of them.
In theory, 3 bits are enough to represent up to 8 (23) combinations.In theory, 3 bits are enough to represent up to 8 (23) combinations.In theory, 3 bits are enough to represent up to 8 (23) combinations.In theory, 3 bits are enough to represent up to 8 (23) combinations.
Most modern digital cameras use 24 bits (8 bits per primary) to represent a color. But more or less can be used, depending on the quality desired. Many early computer graphics cards used only 4 bits to represent a color.
I get 36 .
There are 256 possible values (or characters) in 8 bits.
18 in binary is 10010 Since 18 can't be written in term of 2 to the power x, the number of bits needed is 5. The answer is 5