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How do you display the contents of the memory addresses stored in an element of pointer array?
Wiki User
∙ 8y ago
Every element of a pointer array is a pointer, therefore to access the memory being pointed at by an element, dereference the element. For example:
#include<iostream>
int main (void) {
int* a[10] = {nullptr};
for (int i=0; i<10; ++i) {
a[i] = new int (i+1);
}
std::cout << "Address of array:\n";
std::cout << "a = 0x" << &a << std::endl;
std::cout << "Address of each element in the array:\n";
for (int i=0; i<10; ++i) {
std::cout << "a[" << i << "] = 0x" << &a[i] << std::endl;
}
std::cout << "Value of each element in the array:\n";
for (int i=0; i<10; ++i) {
std::cout << "a[" << i << "] = 0x" << a[i] << std::endl;
}
std::cout << "Dereferenced value of each element in the array:\n";
for (int i=0; i<10; ++i) {
std::cout << "a[" << i << "] = " << *a[i] << std::endl;
}
for (int i=0; i<10; ++i) {
delete a[i];
}
}
Wiki User
∙ 8y ago
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