Look at the flag icon and spam the spot button, it has to be a flag you own or are capping. Also, blow up your vehicles that you leave behind. Thanks, IGN.
In a round, obtain one attack and one defend order.
Bad company 2
first you need to have used a different battlefield game online with the same account as your bc2 account then go onto the bf bc2 website and sign up then click on veteran it should be obvious from there (check YouTube there might be other ways to do this
In Battlefield 3 multiplayer while as a squad leader, the player can issue an attack order to their own squad by aiming the cross hair over an objective, such as an M-COM station in Rush/Squad Rush, or a flag in Conquest and pressing the default command button for the action. To learn the command for issuing an attack order, open the 'Options' menu, then go to 'Controls' and select 'Button Controls'.Note: Sometimes you cannot issue an attack order is you are in too close proximity to an objective or the objective is out of line of sight. In these cases, move away from the objective and in line of sight and try again.Note: Attack and defend orders are issued using the same button/key. Attack orders apply to the attacking team/squad in Rush and Squad Rush. While the defend orders apply to the defenders in those games. For Conquest, attack and defend orders are issued corresponding to whether the flag is under enemy or friendly control.The default button is 'Select' for PlayStation 3 and similar button for Xbox 360.
You can't.
God no.
Someone Else must of used it.
*Heal order is not necessary next to Defend Order- meant to say that Defend Order is all that you'll need for most attacks, and Heal Order is not necessary early on due to weaknesses, or later on, due to Defend Order+Double Team.
Vespiquen learns Defend Order at Level 13, But since a Female Combee doesn't evolve until level 21, You have to get a Heart Scale and get Defend Order through the Move Tutor.
Just keep tapping the A button on the xbox or X on the PS3.
Use the cosine rule: a2 = b2+c2-2bc*cos A BC2 = AB2+AC2-2*AB*AC*cos A BC2 = 32+52-2*3*5*cos 57 BC2 = 17.66082895 BC = 4.20247887 cm in length
Let consider the right triangle ABC with hypotenuse AB and heigth AC then base is BC Pythagorean theorem states that AB2=AC2+BC2 so BC2=AB2-AC2 then BC=sqrt(AB2-AC2)