We have the given equations 4x+y=7 2x-3y=-7
First we want to make it so that we have a variable with the same coefficient in both equations. We will use the x.
so we have 4x+y=7 and 2x-3y=-7. We can multiply or divide both sides of either equation by the same number without changing the equation, so we will take
2x-3y=-7
times 2
2(2x-3y)=2(-7)
distribute
4x-6y=14
now we can use elimination.
4x+y=7
-(4x-6y=-14)
7y=21
divide by 7
7y/7= 21/7
y=3
Now we plug 3 into one of the original equations.
4x+3=7
subtract
4x+3-3=7 -3
4x=4
divide
4x/4= 4/4
x=1
so, the solution to our system of equations is (1,3)
By elimination: x = 3 and y = 0
y=16 x= -4
16
(2,-2)
Solving by the elimination method: x = 7 and y = 2
By elimination: x = 3 and y = 0
y=16 x= -4
16
(2,-2)
Solving by the elimination method: x = 7 and y = 2
The elimination method only works with simultaneous equations, hence another equation is needed here for it to be solvable.
Yes and it works out that x = 3 and y = 4
Solving these simultaneous equations by the elimination method:- x = 1/8 and y = 23/12
x^2y(2x + y)
Solving the above simultaneous equations by means of the elimination method works out as x = 2 and y = 3
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
x = 5, y = -2