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you have to be gay and hitler
(5x + 2)(x + 3)
(4x-3)(x+2)
Yes and it is 4(5x-7) when factored
-1
Can you help me find the value x & Y 3x + 7y = 5 5x-2y = -19
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the answer is x(3+y)
x3+xy-x2y2=x(x2+y-xy2)
(5x + 2)(x + 3)
x(x+5)
To find the xy-trace, set z = 0 in the equation -5x - 2y - 3z = 10. Simplifying, we get -5x - 2y = 10. This is the equation of the xy-trace for the given plane.
6x^2 + 5x + 1 = (3x +1) (2x + 1)
1
(4x-3)(x+2)
x^2 - 5x - 6 Since the coefficient of 'x^(2)' is '1' in this case. we look at the constant '6' . So write down all the factors of 6' . They are 1,2,3,&6. From these four number we select two numbers that add/subtract to '- So if we say -6 + 1 = -5 5'. The coefficient of 'x' Since 6 - 1 = 5 & 2 + 3 = 5 We need to think a little deeper. So we look at the mathemetical signs , which in this case are both negative (-). Since the sign in front of the '6' is negative, this means that the signs in the brackets are different. NB If it was a possitive both the signs in brackets would be the same either both (+) or both (-). So to have a '-5' we can say -6 + 1 = -5 So setting up the brackets ( x 6 )(x 1) So the signs will be (x - 6)( x + 1) Done!!!! Hope that helps!!!!
-5x-2y=10
Yes and it is 4(5x-7) when factored