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As the coefficient of x2 is 1, you just have to look for factors of 20 which differ by 1.
These are obviously 4 and 5 so: (x - 5)(x + 4)
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How do you factorise x squared - 7x 12?
X squared + 7X + 12?
How do you factorise x squared - 3x?
It is: x(x-3) factorized
How do you factorise x squared minus 7 x?
x(x - 7)
How do you factorise x squared - 5x - 6?
x^2 - 5x - 6 Since the coefficient of 'x^(2)' is '1' in this case. we look at the constant '6' . So write down all the factors of 6' . They are 1,2,3,&6. From these four number we select two numbers that add/subtract to '- So if we say -6 + 1 = -5 5'. The coefficient of 'x' Since 6 - 1 = 5 & 2 + 3 = 5 We need to think a little deeper. So we look at the mathemetical signs , which in this case are both negative (-). Since the sign in front of the '6' is negative, this means that the signs in the brackets are different. NB If it was a possitive both the signs in brackets would be the same either both (+) or both (-). So to have a '-5' we can say -6 + 1 = -5 So setting up the brackets ( x 6 )(x 1) So the signs will be (x - 6)( x + 1) Done!!!! Hope that helps!!!!
How do you factorise x squared - 7x?
x(x-7)
How do you factorise 7x-x squared?
7x-x2 = x(7-x)
X squared minus 8x minus 15?
What about it? Factorise it?
How do you factorise x squared plus 7x?
x2+7x x(x+7)
How do you factorise x squared plus 4x?
x2 + 4x = x(x + 4)
How Do you factorise x squared minus 16?
13X squared + 7X + 12
How do you factorise x squared minus 4?
X2 - 4= (x + 2)(x - 2)===========
Factorise x squared plus 3x plus 2?
(x + 2)(x + 1)
