x3 + 2x2 - 8x + 5 = 0
x(2x - 8) + 5 = 0
x3+xy-x2y2=x(x2+y-xy2)
IMPOSSIBLE
No.
It is x = -5
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
x3+xy-x2y2=x(x2+y-xy2)
X3 + 8= (x+2)(x2-2x+4)
-24
IMPOSSIBLE
No.
X(X2 - X)
y2=x3+3x2
No, it is not.
It is x = -5
(xn+2-1)/(x2-1)
If: x3+1 = 65 Then: x3 = 65-1 And: x3 = 64 So: x = 4 by means of the cube root function on the calculator
Realising that 125 is a perfect cube, this is actually pretty easy: x3 + 125 = 0 x3 = -125 x = -5