This factorizes simply if it were x2-11x+10. This is because (-11) squared, minus 4x1x(+10) is 81 is a perfect square. Since it doesn't factorize simply, you have to find the 2 roots given by the usual formula [11+- 4Sqrt(121+40)]/2. Call these two roots A and B. Then the factorization is (x-A)(x-B).
x + x = x(1+1)
It is: x(x-3) factorized
It could be x(1 -1) when factorised
x(x - 7)
x(x+5)
( x - 14 ) ( x + 14 )
x^2 - 5x - 6 Since the coefficient of 'x^(2)' is '1' in this case. we look at the constant '6' . So write down all the factors of 6' . They are 1,2,3,&6. From these four number we select two numbers that add/subtract to '- So if we say -6 + 1 = -5 5'. The coefficient of 'x' Since 6 - 1 = 5 & 2 + 3 = 5 We need to think a little deeper. So we look at the mathemetical signs , which in this case are both negative (-). Since the sign in front of the '6' is negative, this means that the signs in the brackets are different. NB If it was a possitive both the signs in brackets would be the same either both (+) or both (-). So to have a '-5' we can say -6 + 1 = -5 So setting up the brackets ( x 6 )(x 1) So the signs will be (x - 6)( x + 1) Done!!!! Hope that helps!!!!
x(x-7)
7x-x2 = x(7-x)
X(X2 - X)
-47
x2+7x x(x+7)