For a round tank you must find the volume of the tank - V (cubic ft) = pi x radius squared x the depth or height of the tank. The radius and the depth are in feet.
Next take the volume x 7.47 = Gallons of water in the tank
The weight of the tank is the weight of the water x 8.4
example: A water tank that is 2 ft. in diameter and has a height of 5 ft.
The radius is 1/2 of the diameter.
V = 3.1416 x 1 x 5 = 15.708
15.708 x 7.47 = 117.34
117.34 x 8.4 = 986# approx.
Put it in a tank with water. Then total weight of tank + water + stingray, then take out stingray and weigh tank + water. The difference is the weight of the stingray.
6-ft x 2-ft x 1.5-ft = 18 cubic feet. If the tank were 3/4 full, then it would contain 13.5 cubic feet of something. Its weight would be the weight of the tank plus the weight of the contents. We have no way of knowing the weight of the tank. The weight of the contents depends on what substance the tank is 3/4 full of. If water, the weight of the contents is about 842.8 pounds! (rounded)
also the weight of 747 on a full tank
It would weigh just over 1600 pounds
Suppose the weight of the tank is T pounds. Then the weight of the liquid is (500 - T) pounds. The same volume of water will weight (500 - T)/0.8 = 1.25*(500 - T) pounds = 625 + 1.25T pounds.
If the tank is actually filled to the brim (tanks never are) the water would weigh 8.35lbs x 30gallons which is 250.5 lbs. To obtain an accurate total weight you would have to add in the weight of the sand/gravel substrate, and the rocks (decore) and the weight of the empty tank. Then you would subtract the weight of the top 1 inch or so that is always left empty.
That depends on the weight of the fish as compared to the weight of the water their bodies displace. If it's a heavy, dense fish, then the tank with the fish would weigh more. If it's a light, less dense fish, then the tank with water only would weigh more. This assumes that the water displaced has been removed from the tank, right? If you are adding the fish to the water then I think it should increase the weight regardless of the density of your fish. The question then might be, does the fish weigh less when it is swimming than it would on a dry scale?
it is the weight of a vehicle with a full tank of gas and no cargo and no passengers.
tank
. . . . 30 pounds
Yes. Not sure on the exact weights (as it depends on size of tank and pressure of the gas) but you can tell a definite weight difference between an empty and full tank because the compressed air does have a weight
weigh him, and then find his volume by submerging him in a full tank of water, and measuring the amount of water that has overflowed. Once you have the volume, divide his weight by that, and you will have his density