Using Pythagoras' theorem which says that the square on the hypotenuse (in this case the diagonal) is equal to the sum of the squares on the other two sides (which in the case of a square would be equal in length).
so if the diagonal measured 10 units, the square on the diagonal would be 100 square units. And as this = 2*the squares on the other sides, the square on one side would be 100/2 = 50 square units.
As a square has sides of equal length the square on one side is actually the area of the square.
i.e. the area of a square with a diagonal of 10 units is 50 square units.
or generically the area of a square with a diagonal of length 'x' = (x2)/2
Divide the length of the diagonal of a square by 1.4142 (which is the square root of 2) to find the length of a side. Similarly, to find the length of the diagonal of a square, multiply the length of a side by 1.4142.
if a rectangle has width of 5 and diagonal with lenght of 13, what is the area of the rectangle? Use Pythagoras' theorem to find the length of the rectangle which will be 12 5*12 = 60 square units
You can use trigonometry to find the solution. A diagonal divides a square into two triangles, known as "45-45-90" triangles (because of the measures of each angle). According to a law of the same name, the hypotenuse (side opposite of the 90o angle) has a length equal to the length of a leg (side opposite of a 45o angle) times the square root of two. So, since the hypotenuse is a diagonal, you will find that the length of each side of the square is 6 divided by the square root of 2. Find the square of this, and you have the total area: 18 square yards.
If the diagonal is 10 we know all sides are equal so from pythagoraen theorem each side is 7.07 inch length Area = 7.07 x 7.07 = 50
The radius of a square is the radius of the circumcircle, ie the distance from the centre of the square to any vertex, which is half the length of the diagonal of the square. Using Pythagoras: diagonal^2 = side^2 + side^2 → diagonal = √(2 x side^2) area = side^2 → diagonal = √(2 x area) radius = 1/2 x diagonal = 1/2 x √(2 x area) → radius = 1/2 x √(2 x 72 sq in) = 1/2 x √(144 sq in) = 1/2 x 12 in = 6 in.
Given the length of the diagonal of the square ... call it 'D units'. The area of the square is (1/2 D2) (same units)2.
If you are given the area of the square, then the length of each side is the square root of the area. If you are given the length of the diagonal of a square, then the lenght of each side is equal to the length of the diagonal divided by the square root of 2. l=sqrt(a) l=d/[sqrt(2)] l=length of side, d=diagonal, a=area, sqrt means square root
The square has a diagonal measurement of: 1.13 km
Check
32 cm² = 8cm²/2
You cannot. There is not enough information.
The answer will depend on what information about the square you have: its perimeter, area, length of diagonal.
The longest diagonal in a cube is equal to the length of the edge, multiplied by the square root of 3.
Divide the length of the diagonal of a square by 1.4142 (which is the square root of 2) to find the length of a side. Similarly, to find the length of the diagonal of a square, multiply the length of a side by 1.4142.
You multiply the length of a side by the square root of 2.If you only have the area, square root it to find the length of a side.
Square root the area
Cool question ! Answer - half it then cube it to prove it - an example for you if cube diagonal (not square diagonal) is 100, then using pythagoras theorm the square diagonal = 70.71068, If square the square diagonal = 70.71068, then using pythagoras theorm the side length = 50 therefore the volume = 50 ^ 3 = 25000 units works with any numbers