Yoy need to know the molar mass of this solute and the mass of the solute:
moles = total mass/molar mass
number of moles=solute concentration/solute molar mass
Molarity = moles of solute/Liters of solution Or, for our purposes, Moles of solute = Liters of solution * Molarity Moles Na2CO3 = 10.0 Liters * 2.0 M = 20 moles Na2CO3 --------------------------
Molarity = moles of solute/Liters of solution ( find the moles ) 2.36 M NaCl = moles NaCl/5.08 Liters NaCl = 12.0 moles
The answer is 0,16 moles.
molarity = number of moles of solute / volume of solution number of moles of solute = molarity x volume of solution number of moles of solute = 12 (mole/L) x 15/1000 (L) number of moles of solute = 0.18 mole
200 mL is 0.200 L and 0.90 M means 0.90 moles/L So, 0.200 L x 0.90 moles/L = 0.18 moles
Molarity = moles of solute/liters of solution or, for our purposes moles of solute = liters of solution * Molarity moles of AgNO3 = 0,50 liters * 4.0 M = 2.0 moles of AgNO3 needed --------------------------------------
moles of solute over kg of solvent
0.0613 mole fraction = moles solute/(moles solute + moles water) moles water = 1000 g / 18.02 = 55.49 3.62/(55.49 + 3.62)=0.0613
two moles
Molarity = moles of solute/Liters of solution (40 ml = 0.04 Liters) algebraically manipulated, Moles of solute = Liters of solution * Molarity Moles HCl = (0.04 Liters)(0.035 M) = 0.0014 moles HCl ==============
You need to know the moles of solute and the VOLUME of SOLUTION.