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How do you find how much heat is gained in a specific heat problem?
Wiki User
∙ 12y ago
q = C x m x (Tf-Ti), where q is heat, C is specific heat capacity, m is mass in grams, and (Tf-Ti) is change in temperature.
Wiki User
∙ 12y ago
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What is the formula to find specific heat of water Q?
The formula for specific heat is Q = MCdeltaT. DeltaT can also be expresed by (T final - T initial). The specific heat of water is 1 calorie/gram °C = 4.186 joule/gram °C
What factor most influence the amount of energy needed to change the temperature of a substance?
specific heat capacity
How are the amount of heat transferred and the change in temperature of water related?
Hi, heat transferred = mass x specific heat capacity x rise/fall in temperature If heat is lost then fall in temperature If heat is gained then rise in temperature. More the transfer then greater the difference in temperature.
What has higher specific heat water or lead?
Water has much higher specific heat than lead. All metals have fairly low specific heat values.
What is the specific heat constant of oxygen?
heat constant = mass * specific heat capacity * temperature change
The amount of heat gained or lost by a substance is equal to the product of?
mass times the temperature change rimes specific heat capactiy
Factors affect heat gained or lost?
-heat capacity of the object (equal to mass times the specific heat capacity of the object) -overall change in temperature.
How can you find specific heat value at 600 C for a compound?
You have to know mass in grams, energy (q) gained or lost in Joules, and change in temperature,ΔT, in degrees C. ΔT = Final temp - initial temp. The specific heat = q/(m)(ΔT) = J/g•oC
Why is the correct equation rearranged to solve for specific heat?
Probably because somebody wanted, precisely, to find the specific heat.
What is the dimensional formula of energy?
the formula to find specific heat is specific heat= calories/mass X change in temperature.
What is the calculation for specific heat?
Q=cm(delta)T "Q" is the heat "C" is the specific heat "m" is the mass "(delta)T" is the change in temperature * just plug in what you have and then solve for what you don't have...and thats how you find the specific heat of a substance.
When doing a heat exchange problem and the specific heat capacity of the material is not given how do you solve the problem for example If2500caloriesareadded toa1200g sample of Hg howmuchdoestempchan?
3700
A 34.44-g sample of metal is heated to 98.6 degrees Celsius in a hot water bath until thermal equilibrium is reached What is the specific heat of the metal?
Heat lost by the metal = heat gained by the water. Heat gained by the water = 50.0 g x 4.184 J/g K x (28.3-22.2) = 1276 J Heat lost by metal = 1276 J = 34.44 g x Sp Heat x (98.6 - 28.3) Specific Heat = 1276 J / 2421 g K = 0.527 J/g K
How are the amount of of heat transferred and the change in temperature related?
Hi, heat transferred = mass x specific heat capacity x rise/fall in temperature If heat is lost then fall in temperature If heat is gained then rise in temperature. More the transfer then greater the difference in temperature.
How are the amount of heat transferred and change in temperature of water related?
Hi, heat transferred = mass x specific heat capacity x rise/fall in temperature If heat is lost then fall in temperature If heat is gained then rise in temperature. More the transfer then greater the difference in temperature.
How are the amount of heat transferred and the changes in temperature of water related?
Hi, heat transferred = mass x specific heat capacity x rise/fall in temperature If heat is lost then fall in temperature If heat is gained then rise in temperature. More the transfer then greater the difference in temperature.
Let's say there are two objects Object 1 has a high specific heat and Object 2 has a low specific heat Which object would heat more I'll give trust point and recommend contributor?
Heat energy (gained/lost)= mass x specific heat capacity x temperature(rise/fall) Now with this expression we come to know that for a given mass and with a given amount of heat energy in joule, as sp. heat cap is more then rise / fall in temperature will be less and vice versa.
