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a rectangle had a perimeter of 48 and the longest side is 15 find the lenght of a shorter side
You divide the perimeter by the width and you get the lenght
First divide the perimeter by 2 then subtract the diagonal from this. The number left with must equal two numbers that when squared and added together equals the diagonal when squared (Pythagoras' theorem) These numbers will then be the length and height of the rectangle.
to find the perimeter you must add all sides. and to find area you have to multiply lenght and width
The perimeter of a square with a diagonal of 12 centimeters is: 33.9 centimeters.In future, to find out the perimeter of a square when you only know it's diagonal, use Pythagoras or times the diagonal by 2.828427125.This number is irrational, and is like a pi for the diagonals of squares.I call it Tau.It is the relationship between the diagonal of all squares and there perimeter.
The length of the other diagonal works out as 12cm
Length = (1/2 of perimeter) minus (Width) Diagonal = square root of [ (Length)2 + (Width)2 ]
32/4 = 8 units in length
The side of a regular hexagon is 4.8 cm. Find its perimeter.
240 sq m
The perimeter is 31.11 units.
The perimeter of a square with a diagonal length of 24 square root 2 millimeters (33.94 mm) is: 96 mm