yes
program to find maximum of two numbers using pointers
largest number a,b,c,d
You can only do this if the two numbers won't be equal: if(a > b) return a; else return b;
Find your own answers....sucks mahn
int max (int a, int b) { return a>b?a:b; }
Answers down there. range: add the numbers all up and divide how many numbers you have. meadian: put all the numbers in order from smallest to biggest, then find the one in the middle. mean: the biggest minus the smallest. HOPE YOU GET AN A+!!! *************************************************______________________
To find the biggest number in a list using VB.NET, you can use the Max method from the System.Linq namespace. Here's a simple example: Dim numbers As Integer() = {1, 5, 3, 9, 2} Dim maxNumber As Integer = numbers.Max() Console.WriteLine("The biggest number is: " & maxNumber) This code initializes an array of integers, finds the maximum value using Max(), and prints the result.
Find the biggest common factor and divide it by both numbers
you take the biggest number and subtract it by the smallest number.
arg_cnt=$# arg_list=$* biggest=$1 if [ $arg_cnt -eq 0 ]; then echo "$RF there should be minimum 1 argument" exit 1 fi for each_arg in $arg_list do if [ $each_arg -gt $biggest ]; then biggest=$each_arg fi done echo " Biggest number is : $biggest \n" exit 0
Find the largest of two, then find the largest of that value and the third value. int* max (int* a, int* b) { return (a*) > (b*) ? a : b; } int* max_of_three (int* a, int* b, int* c) { return max (max (a, b), c); }
Take the biggest number and subtract it by the smallest number