y=mx+c
The equation of the line is y = mx + c where
m is the gradient of the line and c is the y-intercept
That is, y = 2x + c where c is a constant to be determined.
Since the point (3, 2) is on the line,
2 = 6 + c so that c = -4
So the line is y = 2x - 4
2
-40
33
Point: (1, 4) Slope: -3 Equation: y = -3x+7
gradient = (-2-5) / (2-1) = -7 hence y = -7x + C Since a point on the line is (1,5) 5 = -7 + C from which we have C = 12 The equation is y = 12 - 7x
2
If the point is x=a, y=b ie the point (a,b) , then your line is y-b=m(x-a) where m is the gradient (anything you like).
Both straight line equations will have the same slope or gradient but the y intercepts wll be different
The gradient of the line y = -3 is 0. So any parallel line has the equation y = c.Since it goes though the point (2, 6), c = 6 and so the equation is y = 6.
sda
The general equation of a line isy = mx + cIf the gradient is 3 then m = 3 so thaty = 3x + cSince the point (4,1) lies on this line, these coordinates must satisfy the equation.So 1 = 3*4 + cie c = -11Therefore, the equation is y = 3x - 11
There are an infinite number of ordered pairs. Any point on the straight line which passes through (0,4) and has a gradient of -2 will be an ordered pair for the equation.
Assuming the point is (9, -4), the equation is y = -4.
The vertical line that passes through the point (0, 4) is the Y-axis. Its equation isX = 0
The equation is: y = 4x-22
Write the equation of a line in slope-intercept form that has a slope of -2 and passes through the point (2, -8).
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