v = 2s/t - u
where u=initial velocity, v=final velocity, s = distance and t = time
You use the information you're given, along with the equations and formulas you know that express some kind of relationship between the information you're given and the initial and final velocity.
Use the formula Acceleration = (final velosity - initial velocity)/ time.
Without distance, you have to know time, initial velocity, and acceleration, in order to find final velocity.
You can't. You need either the final velocity or the acceleration of the object as well, and then you can substitute the known values into a kinematics equation to get the initial velocity.
Acceleration is the rate of change of velocity per time, so to get velocity, multiply (acceleration)*(time). This will give the change in velocity over the specific amount of time. You must add the initial velocity to get the final velocity, so we have the formula: Vf = Vo + a*t, where Vo is the initial velocity. This means that you can rearrange to get Vo = Vf - a*t
To find acceleration, you take Vi [Initial Velocity] and you subtract if from Vf [Final Velocity.] (Vi - Vf) If they Vi and Vf are already given, you take the two givens and you subtract them from each other. Vi minus Vf. Do not do Vf minus Vi or it will be wrong. After you do that, you divide your answer from T [Time] (Vi - Vf) a= _____ t Once you get your answer, that will be your acceleration.
Average speed = 1/2 (initial speed + final speed) Time = (distance)/(average speed)
Use s=ut+0.5at^2 (^2 notation for squared)Or calculate the final velocity from the known variables (Initial Velocity, Acceleration and Time)v=u+at Where V = Final Velocity, u = Initial Velocity, a = Acceleration, t = TimeThen calculate displacement (s) using s=0.5(u+v)t
The initial acceleration of an object can be found by calculating the change in velocity over time. This can be done by dividing the final velocity by the time taken to reach that velocity. The formula for initial acceleration is: initial acceleration = (final velocity - initial velocity) / time.
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
If you take initial velocity(Vi) to be zero and the final velocity (Vo) to be a known. Puting the knowns into a triganonomical equation and solving for the value of D would give an answer
v2 - u2 = 2as so that a = (v2 - u2)/2s where u = initial velocity v = final velocity s = distance a = acceleration