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How do you find the imaginary roots of p of x equals x to the fourth plus 2x cubed plus x squared plus 8x minus 12?
Updated: 8/19/2019
Wiki User
∙ 10y agoBest Answer
p(x) = 0 => x4 + 2x3 + x2 + 8x - 12 = 0
=> (x + 3)*(x - 1)*(x2 + 4) = 0
So the imaginary roots of p(x) are the imaginary roots of x2 + 4 = 0
that is x = ±2i
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∙ 10y agoThis answer is:
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