How do you find the intercepts for the equation x2 plus y-49 equals 0?
x2 + y - 49 = 0
At the x-intercepts, y=0:
x2 - 49 = 0
(x+7)(x-7) = 0
x = -7 and x = +7
At the y-intercept, x=0:
y - 49 = 0
y = 49
We have the following quadratic equation: y= x2 + 8x + 15 We need to find the x-intercepts of the equation, or the points where the equation equals zero. To do this, we can factor the equation. Take the following equation: y = (x + a)(x + b) We can factor the equation into this form, if we can find numbers a and b such that: a + b = 8 a * b =…
The equation is -x -16 equals y. You find this by using the equation for a line mx plus b equals y, where 'm' is the slope and 'b' is the y-intercept. From the information given, you have two points which are 0.-16 ans -16,0. You can find 'm' the slope with the equation y2-y1/x2-x1, or -16-0/0- -16. This is -16/16 or -1 for m and the y-intercept is given as -16. So, substitute into…
x + 5y = 0 Subtract 5y from each side of the equation, just to put 'x' and 'y' on opposite sides. x = -5y This is interesting. If EITHER 'x' OR 'y' is zero, then the other one is also zero. The only place on the graph where that is true is the origin. So the line goes through the origin, and the 'x' and 'y' intercepts are both zero.
x2 + y - 49 = 0 At the x-intercepts, y=0: x2 - 49 = 0 (x+7)(x-7) = 0 x = -7 and x = +7 At the y-intercept, x=0: y - 49 = 0 y = 49 General Solution set x=0 to find your y-intercept and set y=0 to find your x-intercept. That's how you will always find your intercepts, no matter what the equation is. Ex. So if you find that when x=0…
Suppose x equals 5 is a solution to the equation 4zx plus 1 equals j where z and j are constants. Find a solution to the equation 8zx plus 5 equals 2j plus 3?
Because there are two different variables and one equation, there is no single answer to this equation. It represents a set of points (x,y pairs) on a straight line. The equation can be rearranged to a slope-intercept form: y = mx + b. y = (-3/5)*x - 3. This line has a slope of -3/5 and intercepts the y-axis at (0,-3).
y=2x2 + 3x-1 To find the zeros of this equation (when y=0) set the equation = 0 0=2x2 + 3x-1 Now, you can either graph the equation in a graphing calculator and find the x intercepts (where the function crosses the x-axis and y=0) or you can factor the quadratic equation by "smiling" or reverse foiling. However, this equation cannot be easily factored. Therefore, using a graphing calculator will provide the correct answer of x=…