First resolve the vertical component of your equation with the formula: Fsinθ (In layman's terms, Force X Sine X anglethrown) This is your initial velocity. At maximum height, velocity is ALWAYS 0. So: Since: V^2 = U^2 + 2as Then: S=(V^2-U^2) / 2a Eg: If we threw a ball at 26ms with an angle of 64: 26sin64=23.36 S= We want to find this value U=23.36 V=0 A=9.81 T= We don't need to know this. S= (0^2 - 545.68^2) / 2x-9.81 S= -545.68 / -19.62 S= 27.8m So the maximum height would be 27.8m Remember, at maximum vertical height V is ALWAYS 0!!!
Kinetic Energy or Potential energy= mass x gravity x height
Without a Question , there is no Answer. Seek/Question and you will find. Seeking is the toad to discovery.
Relatively quite easy, remember all formulas and equations, then on the question itself, look out for the hints they give u like mass, weight, height, friction. Replace them with the letters and u find a solution suitable for those letters.
There are many places where one can find more information about physics. One can find more information about physics at popular on the web sources such as Physics Classroom and Science World.
To find out how things work; to confirm or reject ideas about physics.
For solved problems there are so many websites available. If you type university of physics in your browser it will open a site to physics problems. It gives a easy idea about how to solve physics problems.It has 5 editions. See this and select unit and do the problems well
Without a Question , there is no Answer. Seek/Question and you will find. Seeking is the toad to discovery.
body is projected with a velocity 3o m/s at an angle 30 degree with vertical find maximum height time of flight and range
Q1. Find the minimum and the maximum number of keys that a heap of height h can contain.
Take the derivative of the function.By plugging a value into the derivative, you can find the instantaneous velocity.By setting the derivative equal to zero and solving, you can find the maximums and/or minimums.Example:Find the instantaneous velocity at x = 3 and find the maximum height.f(x) = -x2 + 4f'(x) = -2xf'(3) = -2*3 = -6So the instantaneous velocity is -6.0 = -2x0 = xSo the maximum height occurs at x = 0f(0) = -02 + 4 = 4So the maximum height is 4.
It is the maximum of the z-coordinate - the third of the ordered triplet.
Relatively quite easy, remember all formulas and equations, then on the question itself, look out for the hints they give u like mass, weight, height, friction. Replace them with the letters and u find a solution suitable for those letters.
It is impossible unless the question asks you to find the length when given the volume and height and/or width.
the approximate height of the person if the scaffold is 28 feet tall?
better question what shape is it
Dear Sir, I am Strcuture Engineer,I have a question regarding to maximum displacement in different structures,I am going to design a 27m height water tower which support 20ton mass of water therefore I need the maximum displacement for this type of strcuture so, could you help me in this issu. Thatnks. Najib Azizi
first find suitable apparatus ,design an investigation question and state the hypothesis.
Given the information provided in the question, the only answer is to measure it.