Remember that: (x-a)2+(y-b)2 = radius2 whereas a and b are the coordinates of the circles centre
Rearrange the equation: x2-12x+y2+10y = -12
Complete the squares: (x-6)2+(y+5)2 = 36+25-12 => 49
Therefore: centre = (6, -5) and radius = 7
56
No, it is not.No, it is not.
The equation of the circle with center (h, k) and radius r is of the form(x - h)2 + (y - k)2 = r2x2 + y2 - 10x + 6y = 47 (complete the square)[x2 - 10x + (10/2)2] + [y2 + 6y +(6/2)2] = 47 + (10/2)2 +(6/2)2(x2 - 10x + 52) + (y2 + 6y + 32) = 47 + 52 + 32(x - 5)2 + (y + 3)2 = 81(x - 5)2 + (y + 3)2 = 92So that the center of the circle is (5, -3) and the radius is 9.
Equation: x^2 +y^2 -10x +6y -15 = 0 Completing the squares: (x-5)^2 +(y+3)^2 -25 -9 -15 = 0 So: (x-5)^2 +(y+3)^2 = 49 which is the radius of the circle squared Area of the circle: 49*pi = 154 square units rounded to the nearest integer
This is not possible, since the point (4,6) lies inside the circle : X2 + Y2 = 16 Tangents to a circle or ellipse never pass through the circle
The center of the circle given by the equation (x - 3)2 plus (y + 2)2 = 9 is (3,-2).
(-4,-6)
You are describing a circle, with its center at the origin and a radius of 4 (the square root of 16)
The centre is (-5, 3)
The equation describes a circle with its centre at the origin and radius = √13. Each and every point on that circle is a solution.
I think this means (x+7)squared + (y-5)squared =4squared, which represents a circle centred at -7,+5
no
x2 + y2 = 49
No. C = 2*pi*r is the equation representing the circumference of a circle. The area of a circle is equal to pi*(r^2).
Area of a circle equals pi (~3.14) multiplied by the radius squared. So to find the area of that circle your equation is (3.14)(3)^2 which equals approximately 27.
56
Exactly as it's stated, that equation describes a straight line, not a circle. If you take out the phrase "times 2" from both places where it's used and replace it with "squared", then the equation describes a circle, centered at (-5, 3), with a radius of 5.