since the convex mirror is curved outwards the the focus is behind the mirror
Not sure about mirrors but convex and concave lenses are used to treat conditions such as long/short sightedness.
Yes possible. If we place an object somehow close to the mirror and observe the image. If the image is of the same size as that of the object then it is a PLANE mirror If the image is magnified and erect, then it will be a concave mirror If the image is dimisnished then the mirror is convex in nature.
To find the focal point of a convex mirror, you can use the formula: f = R/2, where R is the radius of curvature of the mirror. The focal point of a convex mirror is located behind the mirror, at a distance equal to half the radius of curvature.
A convenience store
You would typically find a convex mirror in applications such as security mirrors in stores, hospitals, parking lots, and at intersections to provide a wide field of view and help eliminate blind spots. Convex mirrors are also used in vehicles as side mirrors to improve visibility for the driver.
Just by the side of the driver of a bus or lorry which is named as rear view mirror.
I use a mirror with a slight convex curve - like the outside of a spoon, but a lot less bent. But it's hard to find a good one. If you fasten a flat mirror most places on a bicycle, the mirror image will shake around so you can't see it. Also, in a convex mirror, you can see more of the road. But if it's too much bent, too round, then the image is distorted and you can't judge where a vehicle in the mirror really is. The last mirror I bought was described as convex, but actually is flat, so I'm planning to get a piece of car mirror glass cut by a glazier to fit in the frame. That glass is just a little convex. Robert Carnegie, Scotland
convex and its b/c u can see all objects
No, a plane mirror will always produce a virtual image regardless of whether the object is real or virtual. The image appears to be behind the mirror and is not a real image that can be projected onto a screen.
focal length = half radius of curvature 3/2 = 1.5 focal length of mirror is 1.5m 1/f = 1/u + 1/v 1/1.5 = 1/5 +1/v the focal length is negative however because it is a diverging mirror so -1/1.5 = 1/5 + 1/v -1/1.5 - 1/5 = 1/v -10/15 - 3/15 = 1/v -13/15 = 1/v -15/13 = v v = -1.15m the image is 1.15m back from the mirror and is virtual, diminished and upright magnification = v/u -1.15/5 = -0.23 the image bus is 0.23 times smaller than the object
the answer is convex lens! to find this out you should know that concave lens are curved outward and convex lens are curved inward! i hope this helped and if it didn't i would like to apologize for not answering your question, now i bid a fine fairwell to all!
It is easier to find the focal point of a convex lens because the focal point is on the same side as the incoming light, making it more accessible to measure. In contrast, for a concave lens, the focal point is behind the lens and is virtual, making it harder to locate experimentally.