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How do you find the width and perimeter of a rectangle if the length is 31 cm and the width is 5 less than one half of the length?
Wiki User
∙ 12y ago
Let's call the length L and the width W. The width is 5 less than half of the length, so W = (1/2)L - 5. The length is 31, so W = (1/2)(31)-5, which is 10.5. So the length is 31 cm and the width is 10.5 cm. The perimeter is 2 lengths and 2 widths, so the perimeter equals 2L + 2W. In this case, it is 2(31) + 2(10.5) which is 83 cm.
Wiki User
∙ 12y ago
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