Check plug wires I had this problem with my 1999 camaro new wires fixed it.
about 3000 dollars
3000 - 1002 = 1998
Just use Newton's Second Law. That is, divide the force by the acceleration.
Restoring a 1970 Camaro depends on what packages are bought, as well as what needs to be restored or fixed for the car. Restoring can cost at least $3000-$5000 for basic restoration.
1002.
Since 120 is a factor of 3000, it is automatically the GCF of this problem.
Maybe $2500-$3000 if its good shape.
The torque rating for your stock 1968 Camaro 327 cubic inch engine is 235 pounds at 3000 RPMs. The torque rating at 3500 RPMs is 255 pounds.
3000
Mystery Science Theater 3000 Academy of Robots' Choice Awards Special - 1998 TV was released on: USA: 16 March 1998
2nd Annual Mystery Science Theater 3000 Summer Blockbuster Review - 1998 TV was released on: USA: 4 September 1998
To convert 3000 revolutions per minute (rpm) into gravitational force (g), you can use the formula for centripetal acceleration: ( a = \frac{(2\pi \times \text{rpm})^2 \times r}{60^2} ). Here, ( r ) is the radius in meters. To express acceleration in terms of g, divide the result by the acceleration due to gravity (approximately 9.81 m/s²). The final result will give you the acceleration in g's.