answersLogoWhite

0

How do you get a gold ax?

User Avatar

Anonymous

∙ 17y ago
Updated: 8/17/2019

You take a big block of gold and carve it into the shape of a axe i guess.Plus why would you need one?

User Avatar

Wiki User

∙ 17y ago

What else can I help you with?

Related Questions

What are the release dates for Ax Men - 2008 Swamp Gold 5-17?

Ax Men - 2008 Swamp Gold 5-17 was released on: USA: 6 May 2012


What tools were used to build the pantheon?

stone ax, knifes


What is Serena for on Animal Crossing City Folk?

Serena is a goddess that you can find in a fountain ( if you have a fountain in you town). You have to throw an ax into the fountain if you want to see her. Just simply stand in front of the fountain with the ax in your hand and swing the ax. She may give you your ax back, give you a silver ax, give you a gold ax, or she might not give your axe back.


Was a shovel or ax used for mining in the gold rush?

yes becuse i learned about it


Where is can you get 6 gold ax's in final fantasy 12?

nalbina weapons market after you've unlocked bahamut


What is ax times ax?

(ax)(ax) = a2 + 2ax + x2


Is there diamonds on Minecraft pocket edition?

yes there are, there just very rare. you need a iron pick ax to mine the following: coal(can be mined with any pick ax) ,red stone ore, gold ore, and diamonds


How is a Michigan ax different from other styles of ax?

The difference is in the shape of the head of the ax.


What is the homonym of ax?

The homonym of "ax" is "acts." "Ax" is a tool used for chopping, while "acts" refers to actions or performances.


What is the Tagalog of ax?

Tagalog Translation of AX: palakol


What is better the esp ltd ax-414 or the ax-404?

The ESP LTD AX-414.


Write a program to subtract two 16 bit numbers in microprocessor 8086?

.code main proc mov ax,@data mov ds,ax lea dx,msg ;printing msg mov ah,09h int 21h mov ax,x ;ax=x mov bx,y ;bx=y cmp ax,0 ;jump to l3 if ax is negtive jb l3 cmp bx,0 ;jump to l6 if bx is negative jb l6 cmp ax,bx ;if ax<bx,then jump to l1 jl l1 sub ax,bx ;else normal sub mov diff,ax ;diff=result is stored jmp l2 l1: ;iff (+)ax<(+)bx neg bx ;bx=-bx clc add ax,bx neg ax ;-ans=ans mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l3: ;iff (-)ax neg ax ;-ax=ax cmp bx,0 ;jump to l4 if bx is negative jb l4 clc add ax,bx ;ax=(+)ax+(+)bx mov ax,diff mov dx,2dh ;print '-' mov ah,02h int 21h jmp l2 l4: ;if (-)ax & (-)bx neg bx ;-bx=bx cmp ax,bx ;if ax>bx then jump to l5 jg l5 sub ax,bx ;else ax-bx mov diff,ax mov dx,2dh ;print '-' mov ah,02h int 21h jmp l3 l5: ;if(-)ax>(-)bx xchg ax,bx ;exchange ax and bx sub ax,bx ;ax-bx mov diff,ax ;ans is positive jmp l2 l6: ;iff (-)bx neg bx ;-bx=bx add ax,bx ;ax-(-)bx mov diff,ax ;ans will be positive mov ah,4ch int 21h main endp