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If 20.00mL of a 1.50M solution of KBr is diluted to a final volume of 150.0mL what is the new molar concentration?
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
What is the principle is involved in determining the volume of sand in water?
You can very accurately determine the volume of sand using water. If you just take some sand and measure the volume, a lot of the volume you measure is actually the empty space between the sand crystals. If you want the true volume of the sand, you must use the water method.To do this, start with a known volume of water (use a graduated cylinder for instance). Record this volume. The weigh out a certain amount of sand, and add this sand to the water. When you do that, the volume of the water will increase. Record this new volume. Then simply subtract the initial volume from the final volume. This difference is the volume of the sand particles. You can also calculate the density of sand by this method since you weighed the sand before adding it, and the density is just weight ÷ volume.
What is the final temperature of a 20 degree Celsius room temperature pool of water following addition of 960 kJ of energy?
This depends on the volume.
What is the water displacement method?
Mass ____ V2- V1 V1 is the Initial Volume and V2 is the Final Volume. To obtain the Initial volume, measure the amount of water you have in your instrument before putting the object in and record that value. Lastly, measure the amount of water you have now that you've dropped your object in. Record this value too. Now you have your initital and final volume and are almost ready to get your Density! Mass, by the way, is a given. All you have to do is basically weigh whatever object you have :)
What is 4 ml of chemical added to 1liter of water in many ppm concentration?
4ml/1000 = approx 4000 ppm, depending on the final volume after adding 4ml to 1000 ml water
What would the final volume of water be in a graduated cylinder if 0.740 cm3 of silver pellets were added to 11.2 mL of water?
The volume occupied by water will not change, it will remain 11.2cm3 (1ml =1cm3). However, the final volume level will be 11.94cm3, since the silver pellets will displace the same volume of water that it occupies.
A sample of zinc is placed in a graduated cylinder. The initial volume of water= 15.0mL and final volume of water and sample= 24.0mL. Determine the mass of the sample of zinc?
what?
How do you get the volume of an irregularly shaped object?
Using a graduated beaker, add water sufficent to totally immerse the object. Note the initial volume of the water without the object. Put the irregularly-shaped object in the beaker and note the final volume. The difference between the final and initial readings is the volume of the object. This is only possible if the object is not soluble in water. If it is, use some other fluid in which it is not soluble.
When would you use water displacement?
Usually water displacement is used to determine the volume of an object. When the object is added to the water, the amount of displacement can be measured. I don't know if there is an equation to do this, but it most likely involves subtracting the final volume from the initial volume.~Jeff Johnsonwww.jeffjohnsonis.com
If 20.00mL of a 1.50M solution of KBr is diluted to a final volume of 150.0mL what is the new molar concentration?
initial molarity*initial volume= final molarity*final volume Initial molarity= 1.50M Initial volume= 20.00ml Final Volume=150.0ml Thus final molarity =1.50M*20ml/150ml=0.200M. New molar concentration= final molarity
If you have a 100.0-mL graduated cylinder containing 50.0 mL of water. You carefully place a 129-g piece of brass of density 8.56 gmL into the water. What is the final volume reading in the cylinder?
The water will rise by the volume of the brass: volume = mass/density = 129g / 8.56 g/ml ≈ 15.1 ml → final reading ≈ 50.0 ml + 15.1 ml = 65.1 ml
How do you f ind volume of an object using water displacement method?
Fill a market beaker to a specific measured volume. (Eg. 50cm cubed, make sure you have not filled the beaker with water). Now place the object in the beaker with water. The water level should rise (Eg. from 50cm cubed to 60cm cubed). The difference in the original volume and the final volume is the volume of the object. That is the water displacement method.
If you have a 100.0mL graduated cylinder containing 50.0mL of water. you carefully place a 136-g piece of brass (density 8.58gmL) into the water. What is the final volume reading in the graduated cyli?
136 g x 1 ml/8.58 g = 15.85 ml = volume of the piece of brass.According to Archimedes, this will displace an equal volume of water. Thus, the final volume in the cylinder will be 50.0 ml + 15.85 ml = 65.85 ml = 65.9 ml (to 3 sig. figs.)
What is the formula for finding the volume of a copper?
If you refer to a copper coin, simply place it in a measuring glass of water and work out the difference between the start and final volumes; that is the volume of the coin.
What is the principle is involved in determining the volume of sand in water?
You can very accurately determine the volume of sand using water. If you just take some sand and measure the volume, a lot of the volume you measure is actually the empty space between the sand crystals. If you want the true volume of the sand, you must use the water method.To do this, start with a known volume of water (use a graduated cylinder for instance). Record this volume. The weigh out a certain amount of sand, and add this sand to the water. When you do that, the volume of the water will increase. Record this new volume. Then simply subtract the initial volume from the final volume. This difference is the volume of the sand particles. You can also calculate the density of sand by this method since you weighed the sand before adding it, and the density is just weight ÷ volume.
What is the final molarity of 5.84 grams of Na Cl?
Depending on the volume of water ! For 1 L, the molarity is approx. 0,1.
Example of powder volume in pharmacy?
Pv=fv-dv powder volume=final volume-diluent volume
