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what?
What else can I help you with?
Mass in grams of graduated cylinder?
To determine the mass of a graduated cylinder, simply weigh it using an analytical balance or scale. Subtract the empty weight of the balance from the weight displayed when the cylinder is placed on it to obtain the mass of the graduated cylinder in grams.
When a rock is placed in a graduated cylinder containing water the height of the water will what?
remain the same
A nugget of gold is placed in a graduated cylinder that contains 80 ml of water the water level rises to 225 ml after the nugget is added to the cylinder what is the volume of the gold nugget?
The volume of the gold nugget can be calculated by subtracting the final volume (225 ml) from the initial volume (80 ml) of water in the graduated cylinder. Therefore, the volume of the gold nugget is 145 ml.
If an object floats in a beaker as shown assuming the graduated cylinder was empty when the object was placed in the beaker and the beaker was full to the level of the spout what must be true?
stop cheating on gizmos, fool. :)The Answer: The mass of the water in the graduated cylinder is equal to the mass of the object.lol
How do you know which one of two mediums is denser?
You can determine which medium is denser by comparing their densities - the medium with the higher density is denser. This can be done by measuring their masses and volumes, or by observing which one displaces more fluid in a graduated cylinder when placed in it.
If a graduated cylinder has a current water level of 30 ml and you add an object which causes the water level to rise 53 ml what is the volume of the object you placed in the water?
The volume of the object placed in the water is 23 ml. This can be calculated by subtracting the initial water level (30 ml) from the final water level (53 ml).
When Elodea is placed in water and when placed in strong light a space gradually appeared above the water in the graduated cylinder containing the plant The gas in the space above the water was mostly?
oxygen
How can you calculate the volume of an irregularly shaped object?
If the object in question is water proof, and small enough. You can measure the amount of displaced water when it is placed in a tank full of water, this may not work for a lot of things but it can help when attempting to measure some objects.
A nugget of gold is placed in a graduated cylinder that contains 85 mL of water The water level rises to 225 mL after the nugget is added to the cylinder What is the volume of the gold nugget?
The volume of the gold nugget can be calculated by finding the difference in volume before and after adding the nugget. The volume of the gold nugget is 225 mL (final volume) - 85 mL (initial volume) = 140 mL.
11.85 grams of aluminum fragments are placed into 50 ml of water in a graduated cylinder Where will the water line appear on the graduated cylinder knowing that the mass of aluminum is 26.98?
11.85 cannot equal 26.98.Rephrase your question (perhaps you mean that the densityof aluminum is 2,698?)Is all the air evacuated? (no bubbles left attached to the aluminum fragments?)
The volume of water in a gradulated cylinder is 88mL. after a small object is placed in the cylinder the volume increases to 100 mL. what is the volume of the object?
The volume of the object can be determined by calculating the difference in water levels before and after the object was placed in the graduated cylinder. Initially, the volume was 88 mL, and after adding the object, it increased to 100 mL. Therefore, the volume of the object is 100 mL - 88 mL, which equals 12 mL.
If a cylinder of radius 2cm and height 4cm is submerged in a graduated cylinder of radius 3 cm containing a liquid By how much does the liquid rise?
I would say that the liquid rises by 1.77cm... This can be obtained as follows given that cylinder of radius(r)=2cm, height(h)=4cm is submerged in another cylinder, determining the volume of the cylinder being submerged =16*pi. When this cylinder is placed in another cylinder the liquid will rise by an amount which equals the volume of the cylinder being inserted.(By Archimedes principle). Using this 16*pi, determine the height using radius= 3cm , we get h=1.77cm
