145cm cubed
The volume of the gold nugget can be calculated by subtracting the final volume (225 ml) from the initial volume (80 ml) of water in the graduated cylinder. Therefore, the volume of the gold nugget is 145 ml.
Agreed with your correspondent(AnswerBot)!!! However, it must be a huge measuring cylinder if it has a volume of 255 L . I think you mean 255 mL. 255 L is 255 litres = 255,000 mL , which is a quarter of a cubic metre. Please ensure that you correctly insert the units.
The Precious Nugget was named after the owner's childhood nickname, Nugget, and to emphasize the high value and importance placed on the item.
The height of the water will rise a level equal to the volume of the rock.
Any special precautions; you must be careful when working with strong acids or bases, very inflammable and volatile compounds, toxic liquids, radioactive liquids, explosive liquids, etc.
The volume of the gold nugget can be calculated by subtracting the final volume (225 ml) from the initial volume (80 ml) of water in the graduated cylinder. Therefore, the volume of the gold nugget is 145 ml.
Agreed with your correspondent(AnswerBot)!!! However, it must be a huge measuring cylinder if it has a volume of 255 L . I think you mean 255 mL. 255 L is 255 litres = 255,000 mL , which is a quarter of a cubic metre. Please ensure that you correctly insert the units.
To determine the mass of a graduated cylinder, simply weigh it using an analytical balance or scale. Subtract the empty weight of the balance from the weight displayed when the cylinder is placed on it to obtain the mass of the graduated cylinder in grams.
remain the same
stop cheating on gizmos, fool. :)The Answer: The mass of the water in the graduated cylinder is equal to the mass of the object.lol
oxygen
The Precious Nugget was named after the owner's childhood nickname, Nugget, and to emphasize the high value and importance placed on the item.
what?
11.85 cannot equal 26.98.Rephrase your question (perhaps you mean that the densityof aluminum is 2,698?)Is all the air evacuated? (no bubbles left attached to the aluminum fragments?)
If the object in question is water proof, and small enough. You can measure the amount of displaced water when it is placed in a tank full of water, this may not work for a lot of things but it can help when attempting to measure some objects.
The volume of the object can be determined by calculating the difference in water levels before and after the object was placed in the graduated cylinder. Initially, the volume was 88 mL, and after adding the object, it increased to 100 mL. Therefore, the volume of the object is 100 mL - 88 mL, which equals 12 mL.
The height of the water will rise a level equal to the volume of the rock.