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As we know PPM=mg/Kg, if d=1 so PPM=mg/L

At first we must calculate the densty of ethanol in kg, so when we use 0.5L of ethanol it means :

0.789 kg/L = x kg/0.5L : x=0.394 Kg

For a 100 ppm solution of iodine in 0.5 L of ethanol we have 100=mg I2 /0.394 kg

so mg I2 = 39 mg

S.Pourmand

M.Sc. Organic chemistry

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12y ago

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