12+5+5+1
5 + 7 + (6 x √4) = 12 + (6 x 2) = 12 + 12 = 24
The number of combinations of 12 numbers taken 12 at a time (i.e., choosing all 12 numbers from a set of 12) is calculated using the binomial coefficient formula, which is ( \binom{n}{k} = \frac{n!}{k!(n-k)!} ). For ( n = 12 ) and ( k = 12 ), this simplifies to ( \binom{12}{12} = 1 ). Therefore, there is only one combination of 12 numbers from 1 to 12, which includes all the numbers themselves.
There is only one even number that is prime, and that number is the number 2 (two).
12
7+5=12 2-9=3 3x3=9
12 = 1 22 = 1 + 3 32 = 1 + 3 + 5 and so on. The square of the nth whole number is the sum of the first n odd numbers.
Only the number one.
Of the numbers 12 are divisible by--which are 1,2,3,4,6, and 12, only the #1 will divide into 12 and 121.
No, but only in the case of the number 1 (12=1) are square numbers odd.
Yes, you can do 12 + 7 + 5 = 24
(5+7)*(5-3)=12*2=24
No, neither 12 nor 18 are prime numbers. A prime number is a number greater than 1 that can only be divided by 1 and itself. Both 12 and 18 can be divided by numbers other than 1 and themselves, so they are not prime.