by analyzing your three input logic network
by analyzing your three input logic network
Its truth table is: input output 0 1 1 0
Input Output 0 1 1 0
a table like your dinner table where you tell only the truth
If it is boolean logic, typically that is called a Truth Table.
its simple......just you have to make truth table of input and output ......then u will notice that output column can be obtaining by just replacing it by third input or negation of it... in some cases output just hav to connect to one or zero input........for the corresponding output
If you look at the 7486 IC datasheet you can see, it have 4 independence XOR gates with 2 inputs. So you can only use 2 inputs if you see it like that. But if you understand the truth table of XOR gate you can have 3 input application using 7486 IC. Here I will show you how. 1.Get the first 2 input into the first XOR gate. 2.Then get the 3rd input together with the Output from the first 2 input XOR gate into another gate. 3.This output should be the result of 3 input XOR gate. Check this output with 3 input truth table to confirm the answer.
A 4-input majority logic gate outputs a high signal (1) if the majority of its inputs (at least 3 out of 4) are high (1). The truth table for a 4-input majority gate includes 16 rows, reflecting all possible combinations of the four inputs (A, B, C, D). The output is 1 for the following input combinations: 1110, 1101, 1011, 0111, 1111, and any other combination that has at least three 1s. The output is 0 for combinations with fewer than three 1s.
Because if input A *and* input B is true, then the output is true! Truth table of AND gate: ┌─┬─╥───────┐ │A│B║Q (Output)│ ├─┼─╫───────┤ │0│0║0..............│ ├─┼─╫───────┤ │0│1║0............. │ ├─┼─╫───────┤ │1│0║0............. │ ├─┼─╫───────┤ │1│1║1............. │ └─┴─╨───────┘
A truth table is usually a table in which the truth or falsehood of two variables are taken as input and these form the edges of the table. The content of the table shows the truth value of the result of some operation on the variables.
In AND gate , if through both the terminals minimum values were send then the output will be 0 . if either one of the input is maximum , then the output will be 0 , meanwhile if both the input were 1 then the output will be 1 .In OR gate , if both the input are 0 then the output will be 0, but if either the input is 1 then the output will be 1,when both the inputs are 1 then the output will be 1 .
A, B and C are inputs, Q is output.A B C Q0 0 0 10 0 1 00 1 0 00 1 1 11 0 0 01 0 1 11 1 0 11 1 1 0*update*Although the Logism software shows the 3 input XNOR gate output 1 when all 3 are 1, perhaps there is a mistake, and 3 input of 1,1,1 in an XNOR gateoutputs 0. There is a good reason why. In an XOR gate, an even amount of 1 or 0 input will output a 0, and an odd input of 1 (ie: 1, 1, 1) will output a 1. The truth tablefor an XOR gate with 1, 1, 1 input is an output of 1. An XNOR gate will output the opposite of an XOR gate, thus XNOR input of1, 1, 1 should output 0.