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How do you graph y x3 - x?
x3
Which equation x-2 or x3 has a graph that comes closer to the origin?
x3
What does a line graph look like if x-2 and x3?
A line graph needs an equation. x-2 and x3 are expressions: neither is an equation.
Graph the system of inequalities y-2 and x3?
Graph the following Inequalities: x > 3
What is the correct graph ffor x3 and x-2?
what is the anwer for x=3 and x=2
What is X3 - X?
This depends on what you mean by "X3". If the equation is x3-x, then the graph would increase up to about y=0.385, crossing the x-axis at x=-1, then decrease to y=-0.385, crossing the origin, then begin to increase again, crossing the x-axis at x=1. If you just mean x*3-x, then the answer would be 2x. You just enter the function in as f(x)=x^3-x and it will tell you the graph. For future reference, x3 is x^3, not x3.
How do you graph y equals x3?
The graph is a diagonal line with a slope of 1, passing through the x-axis at (3, 0) and the y-axis at (0, -3), extending from the lower left to the upper right.
An equation of the line tangent to the graph of y equals x3 plus 3x2 plus 2 at its point of inflection is?
(a) y = -3x + 1
How does the shape of y equals x2 differs from the graph of y equals x3?
y = x2 is an (approximately) U shaped graph that is entirely above the x axis and is symmetric about the y axis. y = x3 is asymptotically negatively infinite when x is negatively infinite and positively infinite when x is positively infinite. It is symmetric about the line x+y=0.
When is y2 equals x3 plus 2 a function?
If the function is to be continuous, then it is a function if x3 + 2 ≤ 0 or if x3 + 2 ≥ 0 but not both. That is, when x3 ≤ -2 or x3 ≥ -2. So x ≤ -1.2599 or x ≥ -1.2599 (approx). The graph is like a parabola that has been tipped on its side and the above procedure takes either the top half of the parabola or the bottom half. That way you can be sure that no vertical line intersects the graph in more than one place. However, that can also be achieved by taking a segment of the curve above the x-axis, then the next segment from below, then above and below and so on.
How do you find the rate of change?
Differentiation of the function would give you an instantaneous rate of change at one point; the tangent line. Repeated differentiation of some functions would give you many such points. f(x) = X3 = d/dx( X3) = 3X2 =======graph and see
How do you find the instantaneous rate of change?
Differentiation of the function would give you an instantaneous rate of change at one point; the tangent line. Repeated differentiation of some functions would give you many such points. f(x) = X3 = d/dx( X3) = 3X2 =======graph and see
