Math and Arithmetic
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Calculus

# How do you graph x squared plus y squared equals 36?

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###### 2011-02-07 13:41:42

The graph is a circle with a radius of 6, centered at the origin.

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X^2 + Y^2 = 36 Y^2 = 36 - X^2 Y = (+/-)sqrt(36 - X^2) A circle. X = (+/-) 6 Y = (+/-) 6

If by d2 you mean d squared then it is non linear

36. 4 squared is 16...16 + 20 - = 36.

Because 6 squared equals 36 and 36 terminates, or ends, which makes it rational.

It is a quadratic equation and its solutions are: x = 4 or x = -9

I guess you mean 4x + 2y = 12 is changed to 4x + 2y = 36. The graph is translated (shifted) up the 7 axis by 24.

this is not a valid equation. I assume you mean: 2X+8Y=36 in which case the graph is a line with a slope of 1/4 and a y-intercept at 9/2 or 2X+4Y+2=36 in which case the graph is still a line with a slope of 1/2 and a y-intercept at 17/2

x2 + 12x + 36 = 0(x + 6) (x + 6) = 0x+ 6=0 ;x + 6 = 0x = -6 ; x = -6

A squared = 6x6 = 36 B squared = 8x8 = 64 Square root of 36+64 = 10 Given: a2 + b2 = c2 a = 6 and b = 8. We need to find the value of c. a = 6 implies a2 = 62 = (6*6) = 36. b = 8 implies b2 = 82 = (8*8) = 64. a2 + b2 = c2 implies 62 + 82 = c2 c2 = 36 + 64 c2 = 100 c2 = 102 c = 10

If the 64 has a minus sign, then the solution is x = +/-5 Simplifying gives 4x squared = 100 ie x squared = 25...

a2 + 62 = 122 a2 + 62 - 62 = 122 - 62 a2 = 144 - 36 a2 = 108 taking the square root of each side, we get a equal plus or minus the square root of 108, or plus or minus 6 times the square root of 3.

Six 'squared' means six times itself (6 x 6), which equals 36.

It is linear in c and non-linear in d. If both c and d are variables, then it is non-linear.

At the x-intercept, y = 0 So the equation becomes 4x = -36 or x = -9 So the x-intercept is (-9, 0)

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