Please clarify the equation. It does not make sense.
In the hope that it might answer your question, I will determine the length of the curve (hereinafter length) y=3x^43-332x^23 from x=-27 to x=216. length=integral from -27 to 216 of √(1+(129x^42-7636x^22)^2)dx. Solve this by Google searching "definite integral calculator", then clicking on the first result, which should be wolframalpha. Plug in the values there and you will have your answer!
Rydberg's equation is used to find wave length of spectral lines.
By forming a quadratic equation from the information given and then the length and width can be found by solving the equation.
Speed = Frequency * Wave length.
Multiply the length of the base by the vertical height.
If you are trying to find the width of a rectangle with length and area then divide the area by the length. A=LxW. Simply divide both sides of the equation by the length and you'll have the width. W=A/L
length of arc/length of circumference = angle at centre/360 Rearranging the equation gives: length of arc = (angle at centre*length of circumference)/360
You have only one equation [ A = ( L ) ( W ) ] and two unknowns [ L and W ]. You need one more equation to find L and W. The other equation might be the Perimeter equation [ P = 2L + 2W ] orratio of length to width [ L/W or W/L ].
Width x Length x Height = Volume.
You add the five lengths.
2_x_ + 2(x – 4) = 45
You need the height as well to find the area, but the proper equation would be A= 5.5h
a2+b2=c2 ,it is used to find the length of the sides in a right triangle
2(2x) +2x = 100
Equation for perimeter of a rectangle: p = 2l + 2w or: p = 2(l+w) Solve any of the previous equations for the length.
TT=3.14159 so depending on what the length and with is it will be TT x what ever number than carry the decimal and all that stuff.
Write the equation for the perimeter of the rectangle. Replace the known length, and then calculate the width. Once you know that, you can multiply length x width to find the area.
You find the equation of a graph by finding an equation with a graph.
You need more information. Since Volume = Length X Width X Height, you have 3 unknowns, and only equation.
you multiply 2 times the width and 2 times the length ad then add them together. the equation would be 2l+2w=perimeter
you cannot do this; you have area only and two unknowns - lengthand width but only one equation: area = length x width
Assuming the object is a rectangular parallelepiped, use its density to find its volume and solve the equation V abc for c where a, b, and c are the height, length and width respectively
Area = Length*Width so Width = Area/Length. Therefore the Width can be calculated. Then, perimeter = 2*(Length + Width) and everything on the right hand side of the equation is known so the perimeter can be calculated.
Volume = Length * Height * Width That equation can be rearranged to: Width = Volume/(Length * Height) This answer will only work for a cuboid (or a cube) and not any other 3d shape.
A=WxL because of the equation with just an area, length and width can have multiple combinations, however if you have an area as well as a length or a width you can divide the area by either of these to get the other for example L=A/W W=A/L so if you have any two parts of the equation you can find the third
You have to know that [ Volume = (length) x (width) x (height) ]. Then, you can divide each side of that equation by (length x height), and you wind up with Width = Volume/(length x height)