An ordinary queue is a first-in, first-out structure -- analogous with a queue of people waiting to be served. The simplest implementation employs a singly-linked circular list. This is like an ordinary singly-linked list, but the tail node points "down" to the head node rather than to NULL. By keeping track of the tail node (rather than the head node), we gain constant-time access to both the head and the tail through a single pointer.
The basic implementation details of the push and pop methods are as follows:
void push (Node* n) {
if (tail==NULL) { // the queue is empty
n->next = n; // the new node becomes the head (point to self)
} else { // the queue has one or more nodes
n->next = tail->next; // point to the current head of queue
}
tail = n; // the new node becomes the tail
}
void pop () {
if (tail==NULL) return; { // can't pop an empty queue
Node* head = tail->next; // temporarily point to the current head
if (head == tail) { // special case: a queue of 1 node (tail points to self)
free (head);
tail = NULL; // the queue is now empty
} else { // general case: a queue of 2 or more nodes
tail->next = head->next; // set the new head
free (head); // release the old head
}
}
implement the queue ADT using an array
FIFO is a first-in, first out structure. In other words, it is a queue. The most efficient way to implement a queue is with a circular array.
One.
Circular queues are very efficient and work well with low level codes. Ordinary queues are the standard type of queue but they do not maximize memory data well.
Separated queue for every possible priority value.
heap
8798797
An ordinary queue requires constant time access to the first and last elements, because all insertions occur at the back of the queue and all extractions at the front. Thus we require two pointers. However, with a circular queue, the next element after the last element is always the first element, thus we gain constant-time access to both the front and back of the queue through a single pointer to the back of the queue.
Yes it is possible to implement stack and queue using linked list
Add weights to the elements of the queue and use an algorithm to sort the queue every time an element is added.
Two possible solutions: 1. Separated queue for every possible priority value. 2. One shared queue for every elements, sorted by priority.
No.