Day one-Kill 1
Day two-Kill 1
Day three-Kill 1
Day four-Kill 0
Day five-Kill 47
1st day: 42nd day: 43rd day: 44th day: 45th day: 4_________5 days: 20
Take a day off and kill 0. Distribute 4 odd numbers over 4 days as you wish.
Unless you mean at least 20 chickens and/or *within* 7 days, it is impossible, as an odd number of odd numbers will always have an odd number as their sum.
You cannot do this, as adding five odd numbers together will give an odd result.
It cannot be done. Five odd numbers add up to an odd number and so cannot equal 50.
there are 186 odd days if it is NOT a leap year.
The sum of 5 odd numbers cannot be 50.
Take a day off and kill 15 on any two days.
its impossible odd x odd = odd or theres this answer Tie the first fourteen cows to the first fourteen sticks then tie the other 46 cows to the last stick. Anyone would admit that that's an odd number of cows to choose to tie to that stick! Tie the first 13 cows to the first 13 sticks, then tie the others to both of the remaining sticks. Each stick has an odd number of cows.
Yes, the factors of all odd numbers are odd numbers.
Here is one possible way: 2 * 1.25 2 * 1.5 5 * 2.5 It is a very odd way of doing it because, in so doing, none of the cows will remain alive. Suppose you could partition the 18 cows into 9 odd groups. Now, Odd + Odd = Even Even + Even = Even and Even + Odd = Odd So, Odd + Odd + Odd + Odd + Odd + Odd + Odd + Odd + Odd = 18 => Even + Even + Even + Even + Odd = 18 => Even + Even + Odd = 18 => Even + Odd = 18 => Odd = 18 which is false. Therefore, it is impossible to partition 18 cows into 9 odd groups.
The sum of two odd numbers is always even; the sum of three odd numbers is always odd; the sum of four odd numbers is always even; the sum of five odd numbers is always odd; etc