9,8 g concentrated sulphuric acid to 1 L of water (attention to mixing !)
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It depends on just how dilute it is. If we're talking about a strong acid - in this case, acids like perchloric (HClO4), sulfuric (H2SO4), or nitric (HNO3) - and assume that the acid dissociates completely (an ideal situation; in sulfuric acid's case, only the first proton is assumed to dissociate), the pH of the acid is the negative logarithm of its molarity. For example, if you have 1 × 10-3 M (.001 mol · L-1) hydrochloric acid (HCl), its pH will be -log(1 × 10-3) = 3. (Since real life is a non-ideal situation it will actually be slightly higher, but we can disregard that.) That's the easy part and only applies to strong acids. For other (weak) acids of formula HA ⇌ H+ + A-, the pH is dependent upon the acid dissociation constant pKa, in which case pH = pKa + log([A-]/[HA]). Say you have a weak acid with a pKa of 2.0 and a molarity of .01 M. Since pKa = -log(Ka), that means that Ka = .01. The definition of Ka is [A-][H+]/[HA]. Let's call [A-] and [H+] x for this purpose; this makes [HA] = .01 - x; thus, .01 = x2/(.01 - x). Solving for x gives x2 + .01x - .0001 = 0; using the quadratic formula we get .00618 M. Now we may derive the pH. pH = pKa + log([A-]/[HA]) = 2 + log(.00618/.00382) = 2.21.
Molar mass is 44. Linear Formula of PVA is [-CH2CHOH-]n. As C=12 O=16 H=01 Hence (12+2+12+1+16+1=44)
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