1 molar (aka 1M) is a concentration of 1 mole/liter. This means there are 36.4609g (1 mole) of HCl ions dissolved in every liter of solution. In particular, 1.0079g H+ cations (which will form an ionic bond with a water molecule to form H3O+, hydronium) and 35.453g Cl- anions.
This comes out to roughly 3.65% HCl, 96.35% H2O.
Now, I don't believe there is 100% pure HCl around, but one could start with ~36% aqueous HCl with a density of ~1.18 g/mL, and calculate the volume needed. Be sure to add the acid to the water or there could be a violent reaction.
Take 100 mls. 6 molar solution and make it 600 mls. by adding distilled water
1000 ml 1 m HNO3 REQUIRED 65.03 GM
NOW HNO3 DENSITY IS 1.41
SO WE CONVERT MASS/DENSITY =
VOLUME
SO,65.03/1.41= 46.12. ml diluted in 1000 ml dw to make 1m HNO3.
Pour 100 mL of concentrated hydrochloric acid (36,5 %) in 900 ml distilled water.
12.229
your BRAIN!
Amount of HCl is 500cm^3 of .8M HCl = .8 x 500/1000 = 0.4 mol. Volume of 10M acid to give 0.4 mol = .4/10 = 0.04dm^3 = 40cm^3 Add 500 - 40 = 460 cm^3 of water. Caution : 10M HCl is highly corrosive and should be handled with care.
Though this mistake is commonly repeated in text books, I believe that there are no such bounds on pH form 0-14. For example, direct application of the definition of pH (-log10(conc[H+])) shows that the pH of standard 10M nitric acid is -1. This is true of any 10M strong acid, because strong acids are fully ionized in water. Similar reasoning with strong bases reveals that pH can be above 14 (and thus pOH is less than zero).Perhaps this misunderstanding about pH results from the fact that no common pH indicators can read below 0 or beyond 14. another example: HCL with a concentration of 12.93mol/dm3 has apH value of -1.1. In the same way a very highly concentrated alkaline solution could also have a pH maore than 14.
First take 170g of NH3 . Then dissolve in 1L of water
Remember M1V1=M2V2, where M is molarity and V is volume. M1/M2=V2/V1, 10/1=v2/v1, For diluting the acid, we can add acid to water. So, assuming that 10M H2SO4 is having 1ml of water, we should add 1M of H2So4 to 10ml of water.
Alkaline
Acids are vigourous in nature. Therefore, it is completely ridiculous to pour water in acids( as this reaction is exothermic). Therefore, we take a beaker of water and pour the acid drop by drop to the water. Care must be taken and solution must be continuously stirred.
you need 10m to make a guild
10M 10M 10M
Amount of HCl is 500cm^3 of .8M HCl = .8 x 500/1000 = 0.4 mol. Volume of 10M acid to give 0.4 mol = .4/10 = 0.04dm^3 = 40cm^3 Add 500 - 40 = 460 cm^3 of water. Caution : 10M HCl is highly corrosive and should be handled with care.
1 dam3 = 10m*10m*10m = 1000 m3.
16m-10m = 6
1.5-10m = -8.5
I would place this triangle in the category of isosceles triangles, because the 10m side and the 10m side have equal lengths.
10m X 10m
It could be something like 10m x 10m
100cm = 1M 1,000cm = 10M
i have no F@%king idea, maybe if its strong enough like around 10M