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3*(2*4 + 1) = 3*(8 + 1) = 3*9 = 27
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∙ 10y ago
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How do you make 27 using 1 2 3 and 4 only once?
34/(1 + 2)
How do you make 27 from 1 3 4 and 9 Using each number only once?
3^((4+1)/9)=35/9=243/9=27
How do you make 27 from 1 3 4 9 using each number once and only addition multiplication and division?
[Impossible].
How do you get to 27 using the numbers 1 2 4 and 6 only once?
(6*4)+2+1 = 27
How do you make 27 using the numbers 1234?
32 -(1+4) =27
How many whole numbers can you make using the first three whole numbers?
Using 1, 2, and 3, you can make 27 whole numbers.
Using digits 1 to 7 how can you make 100?
13 + 27 + 54 + 6 = 100.
Who can solve this - Using 1 3 4 and 9 make 27 each number can only be used once and must be used using the following functions plus - x and divide?
This is for a job application...but I think it's impossible. Any takers with an answer?
How do you make 27 from 1 2 4 and 6 using each number only once and each arithmetical operation only once?
4! + 1 x 6 ÷ 2 is one way I can figure without using an operation more than once. 4! = 4 x 3 x 2 x 1 = 24. Then by order of operations, perform 1 x 6 ÷ 2 = 3, which is added to 24 to get 27.Another way is: (6/2)^(4-1), which is 3 raised to the 3 power (3 x 3 x 3 = 27).If the limitation on operators is not present, then you can do it by 4 x 6 + 1 + 2 : 4 x 6 = 24, then add 1 and 2 to get 27.
How many combinations can you make using only the numbers 1-7?
8
How do you make 35 using 1 2 3 4 only once?
4*32 - 1 = 4*9 - 1 = 36 - 1 = 35
Write the largest number you can make using each of the digits 7 1 0 2 and 9 just once?
write the largest number you can make using each of the digits 7,1,0,2, and 9 just once
