(6x3) + 2 = 20
6! / (6*6) = 6*5*4*3*2*1 / (6*6) = 20
(3!)!/(3!*3!) = 20, where n! = 1*2*...*n is n-factorial Proof : 3! =1*2*3=6, (3!)!=6!=1*2*3*4*5*6=720, therefore : (3!)!/(3!*3!) = 720/6*6 =720/36 = 20
20/6...both are divisible by 2. so divide them both by 2 and we get 10/3. if you want to make that into a mixed number it would be 3 1/3
10 to 3 both 20 and 6 are divisible by 2 so 20 divided by 2 is 10 and 6 divided by 2 is 3. so 20 to 6 simplified is 10 to 3
3*(-2/3)-6 -2/3 -6 write as -2/3 -6/1 by turning 6 into a fraction then make a common denomanotor -2/3 - 18/3 = -20/3 -20/3 times 3 so write as 3 over 1 equals -60/9 reduced is 6 and 2/3 final answer is 6 2/3 hope that helps
|-20 + 6*3| = |-20 + 18| = |-2| = 2
6 and 2/3 or 20/3
If: y = x² + 9 and y = 6x + 2 then x² + 9 = 6x + 2 → x² - 6x + 7 = 0 → x = (6 ± √(6² - 4×1))/2 = (6 ± √8)/2 = (6 ± 2√2)/2 = 3 ± √2 Substituting in the second to find the corresponding y: → x = 3 - √2 → y = 6(3 - √2) + 2 = 20 - 6√2 or x = 3 + √2 → y = 6(3 + √2) + 2 = 20 + 6√2 The solution is the two points: (3 - √2, 20 - 6√2) and (3 + √2, 20 + 6√2)
6 2/3the mixed number for 20/3 is 6 r 2 , so six and two thirds
6 3/20 = 123/20 = 12.3/2 = 6.15
0.15
20