HCl + NaF -> HF + NaCl
kno3
NaCH3COO or sodium acetate
sodium fluoride
4,5.10e28 molecules of sodium fluoride NaF are equal to 0,745.10e5 moles.
4.25 L of a 0.25 M solution of NaF contain 1,062 moles sodium fluoride.
HCl + NaF -> HF + NaCl
kno3
Sodium fluoride, NaF
F2 + 2 NaCl = 2 NaF + Cl2
3.24
NaCH3COO or sodium acetate
NaF stands for sodium fluoride.
Naf is not in the Oxford English dictionary.
I will dissolve in water to form Na+ and F- NaF <-> Na+ + F- ( NaF is not particularly soluble at room temperature so it might need some heating. After this step the F- anion will react with an H2O molecule to create an HF molecule. F- + H2O <-> FH + OH- Note that F- like other halogens is not likely to attack an hydrogen molecule, however what make F- unique is that the bond it creates is so strong that once it is made, it is very difficult to break. As a result the FH form will exist in solution and accumulate up to a certain amount(the bond can still be broken however, so it is not a strong base), hence why F- is a weak base unlike other halogen ions which are neutral.
The answer to your question is 12.6 because you multiply the .400 times .750 and then you take the answer (0.3) and multiply this times the molar mass of NaF (42) and get 12.6.
the pH increases