There are 2. The chemical formula tells you that there is 1 barium and 2 chlorine.
This equation can be written as 3 BaCl2 (aq) + Al2(SO4)3 (aq) => 2 AlCl3 (aq) + 3 BaSO4 (s).
This equation is 3 BaCl2 + 2 Ag3PO4 -> Ba3(PO4)2 + 6 AgCl.
Correct. Your products will be barium nitrate, which is water soluble (all nitrates are soluble) and silver chloride, which is one of the few insoluble chlorides. There are three equations you can write for this reaction: 1. Normal balanced chemical equation: BaCl2 + 2AgNO3 --> Ba(NO3)2 + 2AgCl 2. Full ionic equation: Ba+2 + 2Cl- + 2Ag+ + NO3- --> Ba+2 + 2NO3- + 2Ag+ + 2Cl- 3. Net ionic equation: Ag+(aq) + Cl-(aq) --> AgCl(s)
BaSO4 is made up of 3 different elements, Ba, S and O. Barium sulfate is a compound.
This equation is 3 BaCl2 + Al2(SO4)3 -> 3 Ba(SO4) + 2 AlCl3.
There are 2. The chemical formula tells you that there is 1 barium and 2 chlorine.
This equation can be written as 3 BaCl2 (aq) + Al2(SO4)3 (aq) => 2 AlCl3 (aq) + 3 BaSO4 (s).
This equation is 3 BaCl2 + 2 Ag3PO4 -> Ba3(PO4)2 + 6 AgCl.
1. Put the mixture of powders in a beaker and add water. 2. Stir vigorously. Sodium chloride is dissolved, barium sulfate not. 3. Filter to separate sodium chloride solution (passes the filter) from barium sulfate as a solid on the filter.
The balanced chemical equation for Barium chloride plus Aluminium sulphate gives Barium sulphate Aluminium chloride is represented as .3BaCl2(aq) + Al2(SO4)3(aq) --> 3BaSO4(ppt) + 2AlCl3(aq).The ppt formed are white in color.
The solution contain ions as: Zn2+, (NO)-3, Ba2+, Cl-. Any reaction.
This equation is: 3 BaCl2 (aq) + Al2(SO4)3 (aq) = 3 BaSO4 (s) + 2 AlCl3 (aq).
Correct. Your products will be barium nitrate, which is water soluble (all nitrates are soluble) and silver chloride, which is one of the few insoluble chlorides. There are three equations you can write for this reaction: 1. Normal balanced chemical equation: BaCl2 + 2AgNO3 --> Ba(NO3)2 + 2AgCl 2. Full ionic equation: Ba+2 + 2Cl- + 2Ag+ + NO3- --> Ba+2 + 2NO3- + 2Ag+ + 2Cl- 3. Net ionic equation: Ag+(aq) + Cl-(aq) --> AgCl(s)
The III is there because as a transition metal, iron can have multiple oxidation states. This means iron is 3+. The charge on each Cl is -1, so you need 3. This gives you FeCl3 Next, Barium has 2+ charge, so you need two OH-'s i.e. Ba(OH)2
Barium Cholride and sulphuric acid create a white precipitate, videos of the reaction is on this website http://jchemed.chem.wisc.edu/jcesoft/CCA/CCA4/MAIN/BACL/PAGE1.HTM
Barium has a charge of -2 and Oxygen has a charge of +2. Oxygen is nature appears as O2, therefore Barium + Oxygen = barium oxide; Ba + O2 = BaO; 2Ba + O2 = 2BaO