Simple: Draw a star! It took my friend 3 YEARS TO FIGURE IT OUT :0
you can't
If you have 8 small triangles made of 16 lines how can you make four small triangles if it is a parallelogram?
Select any vertex and draw 2 lines to the two opposite vertices.
It's really simple- A STAR! I was trying to figure it out and was just like OMG! Easy-peasy
I get 9 triangle with fewer than 9 lines. Draw a square: ABCD (4 lines) Draw the diagonals AC, BD (2 lines) which meet at X in the centre. On a separate part of the page, draw triangle PQR (3 lines). That is 4 + 2 + 3 = 9 lines. The triangles are: ABC, BCD, CDA, DAB, AXB, BXC, CXD, DXA, and PQR 9 triangles with 9 lines. Could have done 13 triangles with 7 lines by drawing a line from A to BC.
Yes, by intersecting them.
If you draw a single square, and then put one X through it, you have 4 triangles. Put another X through it and you have 8. Now, if you want to make four triangles, simply remove the two diagonal lines in the center, and it will create four triangles. Now, since they're separated by the other triangles, it would mean removing four lines, but that is still your answer.
Triangles do not have parallel lines but as right angles triangles they do have perpendicular lines that meet at 90 degrees.
no they do not they have to be equal so that proves there is NO lines of symmetry * * * * * It depends on the triangle. Equilateral triangles have 3 lines of symmetry, Isosceles triangles have 1 and all other triangles have none.
form triangles side by side
it can/t be
triangles simply does not have them. The lines in a triangle conects after a path that does not produce paralel lines.