dissolve 10g of TCA in 100ml distilled water.
6 litres of 50% + 4 litres of 25%
7 liters of a 20% acid solution consists of 1.4 liters of acid (20% of the total volume) mixed with 5.6 liters of water (80% of the total volume). The amount of acid isn't going to change in the new solution. You are just going to add enough water to make it a 10% solution instead of a 20% solution. So it will be more dilute. That means that 1.4 liters of acid will represent 1/10 of the volume of the new solution. So the total volume of the new solution will be 10 x 1.4 or 14 liters. The amount of water in the new solution will be 14 - 1.4 = 12.6 liters. That is a difference of 12.6 - 5.6 = 7 liters from the amount of water you started with. So you need to add 7 liters of water to the original 20% solution to make it a 10% solution. This makes sense because if you double the amount of the mixture from 7 liters to 14 liters and the amount of acid is unchanged, the solution will be half as strong.
You have 6 litres of alcohol in 24 litres of water You need to add x litres to make 6 equal to 15% of 30 + x. 6 is 15% of 40, so x = 10
25% ammonia solution means 25g Ammonia in 100ml of water. To convert it into moles i.e for 1000ml solvent, 25x100=250 which means 250g of ammonia is present in 1000ml of water to make a 25%solution. To convert it into molar solution we will divide 250 by the molecular mass of ammonia i.e 17. 250/17= 14.71M This means that 25% ammonia solution contains 14.71 moles of ammonia. Now we will use the formula M1V1=M2V2 Let's say we want to make 10 molar solution in 500ml water. Then, M1=14.71 V1=? M2=10 V2=500 Putting values in the above equation: 14.71xV1 = 10x500 V1 = 10x500 / 14.71 = 340ml We will take 340ml of the 25% ammonia solution and make the volume up to 500ml with water. This will be our 10 molar solution of Ammonia.
30 liters of a 10 % solution of fertilizer has .1(30) = 3 liters of fertilizer 1 liter of 30% solution has .3 liter of fertilizer 10 liters of 30% solution has 3 liters of fertilizer so, the chemist needs 10 liters of the 30% solution and 20 liters of water to make 30 liters of a 10% solution.
144liters
256 liters
6 litres of 50% + 4 litres of 25%
4.84
Add 0,8 L of water.
Take 100 gm acetic acid. With 99% purity,it contains 99 gm of Acetic Acid. To make 5% solution,add 1880 gms water.
50% citric acid powder = 50 g citric acid/100 g 4% citric acid solution = 4 g citric acid/100 ml distilled water Determining how much citric acid powder to use is based upon how much citric acid solution you wish to make. To make 100 ml of solution, you should use 8 g of powder.
If it is a mixture, then yes. Pure acetic acid is one hundred percent acetic acid, while vinegar is 5 or 10 percent acetic acid in water. You can make a solution of acetic acid and alcohol.
A 50 ml solution that is 10% acid will consist of 5 ml of acid (10% of the volume) and 45 ml of water (90% of the volume). You're not adding any water, but you want to add enough acid to make a solution that is 50% acid and 50% water. You will need to have a total of 45 ml of acid in the mixture to make it a 50/50 solution, since the amount of water is also 45 ml. You have 5 ml in there already, so you would need to add 40 ml of acid. That would make a total 90 ml solution that is 50% water (45 ml) and 50% acid (45 ml).
so it is 33% already. You need to dilute every 33ml with 30.5ml solvent and adding 2.5ml of the solution. Feel free to message if you need further explaining
If it's a 4% solution by mass, you want 4.167g of acetic acid (25g/6)
Weigh 60 grams of Glacial Acetic acid into a 1 liter volumetric flask. Make up to the 1 liter mark with distilled water. There is now a 6% (w/v) solution.